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Lemur [1.5K]
3 years ago
8

Atoms that have a positive or negative electrical charge are called ________.​

Chemistry
1 answer:
hjlf3 years ago
4 0

Explanation:

They are called or known as cations

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Alkenes can be converted to alcohols by hydroboration–oxidation. Draw a structure showing one of the alcohols formed in the foll
makkiz [27]

Answer:

  1. CH3CH2CH2CH2CHCH2OH  Hexanol

Explanation:

          Hydroboration reaction of Hexene yields Hexanol

5 0
3 years ago
How many moles of h2o are equivalent to 97.3 grams of h20
g100num [7]

Answer : 5.405 moles of H_2O are equivalent to 97.3 grams of H_2O

Solution : Given,

Mass of H_2O = 97.3 g

Molar mass of H_2O = 18 g/mole

Formula used :

\text{ Number of moles}=\frac{\text{ Given mass}}{\text{ Molar mass}}

or,

\text{ Number of moles of }H_2O=\frac{\text{ Given mass of }H_2O}{\text{ Molar mass of }H_2O}

Now put all the given values in this formula, we get the moles of H_2O

\text{ Number of moles of }H_2O=\frac{97.3g}{18g/mole}=5.405moles

Therefore, 5.405 moles of H_2O are equivalent to 97.3 grams of H_2O

6 0
3 years ago
Suppose a current of is passed through an electroplating cell with an aqueous solution of agno3 in the cathode compartment for s
WARRIOR [948]

The given question is incomplete. The complete question is:

Suppose a current of 0.920 A is passed through an electroplating cell with an aqueous solution of agno3 in the cathode compartment for 47.0 seconds. Calculate the mass of pure silver deposited on a metal object made into the cathode of the cell.

Answer:   0.0484 g

Explanation:

Q=I\times t

where Q= quantity of electricity in coloumbs

I = current in amperes = 0.920 A

t= time in seconds = 47.0 sec

Q=0.920A\times 47.0s=43.24C

AgNO_3\rightarrow Ag^++NO_3^-

Ag^++e^-\rightarrow Ag

96500 Coloumb of electricity electrolyzes 1 mole of Ag

43.24 C of electricity deposits =\frac{1}{96500}\times 43.24=0.00045moles of Ag

\text{ mass of Ag}={\text{no of moles}\times {\text{Molar mass}}=0.00045mol\times 108g=0.0484g

Thus the mass of pure silver deposited on a metal object made into the cathode of the cell is 0.0484 g

6 0
3 years ago
The atomic mass of calcium is calculated by adding the mass (amount) of
3241004551 [841]

Answer:

B. Protons and Neutrons

6 0
2 years ago
Read 2 more answers
aluminum bronze contains 92.0% of copper and 8.0% aluminum. what maximum mass of aluminum bronze can be prepared from 73.5g of c
slega [8]
The answer is 79.9 g.

Copper takes 92.0% of aluminum bronze and it is a limiting factor. We have aluminum in excess, so we need to make a proportion.
If 73.5 g of copper are 92.0%, how many g of aluminum bronze will be 100%:
73.5 g : 92.0% = x : 100%.
x = 73.5 g : 100% * 92.0%
x = 79.9 g

Therefore, from 73.5 g of copper and 6.4 g of aluminum (since 79.9 g - 73.5 g = 6.4 g), maximum 79.9 g of aluminum bronze can be prepared.
4 0
2 years ago
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