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2 years ago

What cause the ratio of PV/RT to drop below 1 when 1 mole of

Chemistry

1 answer:

pentagon [3]2 years ago

6 0

Answer:

pressure and temperature are directly proportional.

Explanation:

At constant temperature and pressure the volume of a gas is directly proportional to the number of moles of gas. Also given a constant temperature and volume the pressure of a gas is directly proportional to the number of moles of gas.

This means that if V is constant then

P = n (RT/V) then n= PV/RT. As P is increased, T is also increased thereby decreasing the value of n since pressure and temperature are directly proportional.

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What did Rutherford’s gold foil experiment indicate?

Klio2033 [76]

The answer would be D.

4 0

3 years ago

Un catión trivalente contiene 75 nucleones y 45 neutrones, Señale el número de electrones que posee dicho catión.

FromTheMoon [43]

Answer:

10 electrons

Explanation:

5 0

2 years ago

True or False? Not all compounds will dissolve in water.

In-s [12.5K]

Answer:

False

Explanation:

Polar molecules and ionic compounds dissolve in water, not nonpolar molecules

4 0

3 years ago

The bonds of oxygen molecules are broken by sunlight. The minimum energy required to break the oxygen-oxygen bond is 495 kJ/mol

olga_2 [115]

Answer:

The wavelength of sunlight is required to break the bond in one oxygen molecule is 242 nm.

Explanation:

Energy required to break the 1 mol oxygen-oxygen bond:

=495 kJ=495000J

1 mol = $6.022\times 10^{23}$ molecules

Energy required to break 1 molecule of oxygen molecule= E

= $E=\frac{495000 J}{6.022\times 10^{23}}=8.219\times 10^{-19} J$

The energy required to break the 1 molecule of oxygen is equal to enrgy of one photon of a sunlight.

$E=\frac{h\times c}{\lambda}$

where,

$\lambda$ = wavelength of the light

E = energy of the photon

h = Planck's constant = $6.63\times 10^{-34}Js$

c = speed of light = $3\times 10^8m/s$

$\lambda=\frac{h\times c}{E}$

$\lambda =\frac{6.63\times 10^{-34}Js \times 3\times 10^8m/s}{8.219\times 10^{-19} J}=2.42\times 10^{-7} m=242 nm$

The wavelength of sunlight is required to break the bond in one oxygen molecule is 242 nm.

4 0

3 years ago

Wastewater from a cement factory contains 0.280 g of Ca2+ ion and 0.0220 g of Mg2+ ion per 100.0 L of solution. The solution den

faltersainse [42]

Answer: The concentration of $Ca^{2+}\text{ and }Mg^{2+}$ ions are 2.797 ppm and 0.212 ppm respectively.

Explanation:

To calculate the mass of solution, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Volume of gold = 100 L = 100000 mL (Conversion factor: 1 L = 1000 mL)

Density of gold = 1.001 g/mL

Putting values in above equation, we get:

$1.001g/mL=\frac{\text{Mass of solution}}{100000mL}\\\\\text{Mass of solution}=1.001\times 10^5g$

To calculate the concentration in ppm (by mass), we use the equation:

$ppm=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6$

Calculating the concentration of calcium ions:

Mass of $Ca^{2+$ ions = 0.280 g

Putting values in above equation, we get:

$ppm(Ca^{2+})=\frac{0.280g}{1.001\times 10^5}\times 10^6=2.797ppm$

Calculating the concentration of magnesium ions:

Mass of $Mg^{2+$ ions = 0.0220 g

Putting values in above equation, we get:

$ppm(Mg^{2+})=\frac{0.0220g}{1.001\times 10^5}\times 10^6=0.212ppm$

Hence, the concentration of $Ca^{2+}\text{ and }Mg^{2+}$ ions are 2.797 ppm and 0.212 ppm respectively.

7 0

3 years ago