Answer:
Kindly check the explanation section.
Explanation:
When the Arsenic acid,H3AsO4 is put in water it dissociates to form or give out 1 proton, 2 protons or 3 protons that is 1H^+, 2H^+ and 3H^+. Check the equation showing the dissociation reactions as given below;
H3AsO4 ===========> H^+ + AsO4^-
H3AsO4 ===========> 2H^+ + AsO4^2-
H3AsO4 ===========> 3H^+ + AsO4^3-
Therefore, the total charge balance is given as:
[H^+] =[OH^-] + [ AsO4^-] + 2[ AsO4^2-] + 3[ AsO4^3-].
Kindly note that the [OH^-] is from water.
Answer:
(S)-3-methoxy-3-methylbutan-2-ol
Explanation:
In this case, we have an <u>epoxide opening in acid medium</u>. The first step then is the <u>protonation of the oxygen</u>. Then the epoxide is broken to generate the most <u>stable carbocation</u>. The nucleophile (
) will attack the carbocation generating a new bond. Finally, the oxygen is <u>deprotonated</u> to obtain an ether functional group and we will obtain the molecule <u>(S)-3-methoxy-3-methylbutan-2-ol</u>.
See figure 1
I hope it helps!
Answer:
blue react with bases to create a neutral solution
Explanation:
A strong acid will react with a strong base to form a neutral (pH = 7) solution.