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Misha Larkins [42]
4 years ago
7

In the cross AaBbCc × AaBbCc, what is the probability of producing the genotype AABBCC? In the cross AaBbCc × AaBbCc, what is th

e probability of producing the genotype AABBCC? 1/16 1/32 1/4 1/64 1/8
Biology
1 answer:
uranmaximum [27]4 years ago
4 0

Answer:

1/64

Explanation:

Parent 1: AaBbCc

Parent 2 : AaBbCc

When the cross is checked for individual gene:

Aa X Aa =

    A     a

A  AA  Aa

a   Aa  aa

Probability of producing an AA organism is 1/4

Similarly, probability of producing a BB from Bb X Bb would be 1/4

Probability of producing a CC from Cc X Cc would be 1/4

Hence, probability of producing an AABBCC would be:

1/4 * 1/4 * 1/4 = 1/64

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