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Marianna [84]
3 years ago
13

Like chordates, all invertebrates have

Biology
2 answers:
mamaluj [8]3 years ago
5 0
I just took the test and the correct answer is B. eukaryotic cells
BabaBlast [244]3 years ago
3 0

Correct answer is option b. i.e. eukaryotic cells.

There are 5 kingdoms in which living organisms have been classified:

1) Monera

2) Protista

3) Fungi

4) Plantae

5) Animalia

It is only kingdom Monera which comprises organisms made up of prokaryotic cells.  Rest all other kingdoms have organisms made up of eukaryotic cells regardless of whether they have tails or they are tailless, they have backbones or not and whether they have  pharyngeal pouches or not.

Animal kingdom has many phylums. Animals within the animal kingdom are subdivided into vertebrates and invertebrates. Out of these animals, some have notochord and they are therefore called as chordates. Also, all the vertebrates are chordates but all chordates are not vertebrates. All the animals in the animal kingdom are made up of eukaryotic cells whether they are vertebrates, invertebrates, chordates or non- chordates.

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A sample compound with a molar mass of 34.00g/mol is found to consist of 0.44g H and 6.92g O. Calculate both empirical and molec
ipn [44]

Answer:

Empirical: OH

Molecular: H_{2} O_{2}

Explanation:

First of all, we are going to use the formula: mass = no. moles x Molar Mass And rearrange it to find No. moles: No. moles = mass/Molar Mass

Let's start with Hydrogen:

The given mass is 0.44g, and hydrogen's molar mass is 1.01, therefore the number of moles is: 0.44/1.01 = 0.4356

Now we do the same for Oxygen:

Given mass = 6.92, Molar mass of Oxygen = 16.00, No. Moles = 6.92/16.00 = 0.4325

Now we identify the smaller one (Oxygen as 0.4325 < 0.4356) and we divide both values by that number:

0.4325/0.4325 = 1

0.4356/0.4325 = 1.01

We round both to the nearest 0.2 or 0.25 (depending on what you're taught), and we get: 1 and 1.

This means that the empirical formula has one of each: OH

Now to find the molecular formula we find the relative mass of OH and divide the given mass by that:

M(OH) = 16.00+1.01 = 17.01

34.00/17.01 = 2

We now multiply both by this number to get:

H_{2} O_{2}

Hope this helped!

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