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2 years ago

What effect does thermal energy have on the rate of chemical reactions?

Chemistry

2 answers:

ivolga24 [154]2 years ago

6 0

Answer: temperature

Explanation: umm cuz I know things.. lol

Zielflug [23.3K]2 years ago

5 0

Answer:

The temperature, however, greatly affects the rate of a chemical reaction. As you heat a substance, its molecules move faster and are more likely to react. Some reactants even require some heat to initiate a reaction. Reaction Rates and Temperature

Explanation:

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Calculate the mass in grams of carbon dioxide produced from 11.2 g of octane (C8H18) in the reaction above.

Ray Of Light [21]

Answer:

34.6g

Explanation:

Given parameters:

Mass of Octane = 11.2g

Reaction expression;

2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O

Mass of octane = 11.2g

Unknown:

Mass of carbon dioxide produced = ?

Solution:

From the balanced reaction equation;

2 mole of octane produced 16 moles of carbon dioxide

From the given specie, let us find the number of moles;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of C₈H₁₈ = 8(12) + 18(1) = 114g/mole

Number of moles of octane = $\frac{11.2}{114}$ = 0.098mole

2 mole of octane produced 16 moles of carbon dioxide

0.098 mole of octane will produce $\frac{0.098 x 16}{2}$ = 0.79mole of CO₂

Mass of CO₂ = number of moles x molar mass

Molar mass of CO₂ = 12 + 2(16) = 44g/mol

Mass of CO₂ = 0.79 x 44 = 34.6g

8 0

3 years ago

What quantity is the same among atoms of the same element?

Vedmedyk [2.9K]

Answer:

Neutrons or Neutral atoms

Explanation:

Neutral atoms of each element contain an equal number of protons and electrons. The number of protons determines an element's atomic number and is used to distinguish one element from another.

8 0

2 years ago

Use the Henderson-Hasselbalch equation, eq. (3), to calculate the pH expected for a buffer solution prepared from this acid and

notka56 [123]

Answer:

$pH=4.56$

Explanation:

Hello there!

In this case, given the Henderson-Hasselbach equation, it is possible for us to compute the pH by firstly computing the concentration of the acid and the conjugate base; for this purpose we assume that the volume of the total solution is 0.025 L and the molar mass of the sodium base is 234 - 1 + 23 = 256 g/mol as one H is replaced by the Na:

$n_{acid}=\frac{0.2g}{234g/mol}=0.000855mol\\\\n_{base}= \frac{0.2g}{256g/mol}=0.000781mol$