Explanation:
the investigation lasts for 7 days.
hope this helps you.
Answer:
i is the correct answer.
Explanation:
the RAM of aluminum is indeed 27. And since the RAM of substances are measured in terms of the C-12 isotope then R indeed explains why the RAM Al is 27.
<h3>
Answer:</h3>
322.7 kW
<h3>
Explanation:</h3>
- Power refers to the rate at which work is done.
- Therefore; Power = Work done ÷ time
- It is measured in joules per seconds or Watts
In this case, we are required to convert 0.3227 MW to kilowatts
We need to know that;
- 10^6 watts = 1 Megawatts(MW)
- 10^3 Watts = 1 kilowatts (kW)
Therefore;
10^3 kW = 1 MW
Therefore, the suitable conversion factor is 10^3kW/MW
Hence;
0.3227 MW is equivalent to;
= 0.3227 MW × 10^3kW/MW
= 322.7 kW
Thus, the peak power output is 322.7 kW
Answer: Concentration of
in the equilibrium mixture is 0.31 M
Explanation:
Equilibrium concentration of
= 0.729 M
The given balanced equilibrium reaction is,

Initial conc. x 0 0
At eqm. conc. (x-2y) M (y) M (3y) M
The expression for equilibrium constant for this reaction will be:
3y = 0.729 M
y = 0.243 M
![K_c=\frac{[y]\times [3y]^3}{[x-2y]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5By%5D%5Ctimes%20%5B3y%5D%5E3%7D%7B%5Bx-2y%5D%5E2%7D)
Now put all the given values in this expression, we get :



concentration of
in the equilibrium mixture = 
Thus concentration of
in the equilibrium mixture is 0.31 M