A chemical engineer must report the average volume of a certain pollutant produced by the plants under her supervision. Here are
1 answer:
Answer:
9.2 L is the average volume should the chemical engineer report.
Explanation:
Volume of pollutant from Cross creek plants 10.88 L
Volume of pollutant from Oglala plants = 0.92 L
Volume of pollutant from Platte plants = 15.82 L
Average volume pollutants will be given by :
9.2 L is the average volume should the chemical engineer report.
You might be interested in
2 C₁₇H₁₉NO₃ + H₂SO₄ → Product
Moles of H₂SO₄ = M x V(liters) = 0.0116 x 8.91/1000 = 1.033 x 10⁻⁴ mole
moles of morphine = 2 x moles of H₂SO₄ = 2.066 x 10⁻⁴
Mass of morphine = moles x molar mass of morphine = 2.066 x 10⁻⁴ x 285.34
= 0.059 g
percent morphine =
=
= 8.6 %
Moles of H₂SO₄ = M x V(liters) = 0.0116 x 8.91/1000 = 1.033 x 10⁻⁴ mole
moles of morphine = 2 x moles of H₂SO₄ = 2.066 x 10⁻⁴
Mass of morphine = moles x molar mass of morphine = 2.066 x 10⁻⁴ x 285.34
= 0.059 g
percent morphine =
=