1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vfiekz [6]
3 years ago
10

Energy can be .................. From one form to another................. Can be burned to make heat or electricity.

Chemistry
1 answer:
nataly862011 [7]3 years ago
3 0

Answer:

transferred

Energy

Explanation:

Energy is the ability to change the state of bringing about a work leading to movement or generating electromagnetic radiation. There are actually many forms of energy. So, kinetic energy is a form of energy related to the movement of a body. The combustion, in turn, retrieves the potential energy chemical contained in fuels. Solar panels capture light energy to transform it into electrical energy.

You might be interested in
Urgent plzz help meeee thx
MakcuM [25]

Answer:

8

Explanation:

From the question given above, the following data were obtained:

t–butyl ion = (CH₃)₃C⁺

Number of valence electron =?

The valence electron(s) talks about the combining power of an element or compound as the case may be.

Considering the t–butyl ion, (CH₃)₃C⁺ we can see that it has a charge of +1 indicating that it has given out 1 electron to attain the stable octet configuration which has a valence electrons of 8. Thus, the valence electron of t–butyl ion, (CH₃)₃C⁺ is 8

5 0
2 years ago
The country like Nepal with diversity must have competition and cooperation <br>justify​
Len [333]
Help????? You need to write as if you are Dmitri Mendeleev and you have just made your proposed version of the periodic table. You need to write to the Royal Society of Chemistry in London explaining:
• Who you are
• What your periodic table is like, the groups, elements and features
• Why you think your periodic table is correct
• How you have built on the work of others or why you think their work is not
correct
3 0
3 years ago
To insert a thermometer into an adapter, use choose. To prepare the thermometer. Then, hold the thermometer choose. The adapter
vova2212 [387]

To insert a thermometer into an adapter, use <u>mineral oil</u> to prepare the thermometer. Then, hold the thermometer <u>close to</u> the adapter and<u> slowly turn</u> the thermometer into the adapter.

The term "temperature" refers to a measurement of how cold or hot an actual physical object is. It is measured with a thermometer, which gives readings in Celsius, Kelvin, and Fahrenheit (°C, K, and °F).

The average kinetic energy of the particles in a given substance is often measured by temperature. A thermometer is a tool used to gauge a substance's or a body's temperature (degree of hotness or coolness). It is a bulb-shaped piece of thin glass that usually contains either coloured alcohol or mercury.

In order to get readings throughout the distillation process, a thermometer adapter is used with a temperature probe. Use mineral oil to prepare or make the thermometer suitable before inserting it into the adapter. After that, slowly insert the thermometer into the adaptor while holding it close to it.

Learn more about thermometer:

brainly.com/question/2339046

#SPJ4

7 0
1 year ago
Yeast and other organisms can convert glucose (C6H12O6) to ethanol (CH3CH2OH) by a process called alchoholic fermentation. The n
NISA [10]

Answer:

8.37 grams

Explanation:

The balanced chemical equation is:

C₆H₁₂O₆     ⇒   2 C₂H₅OH (l) + 2 CO₂ (g)

Now we are asked to calculate the mass  of glucose required to produce 2.25 L CO₂ at 1atm and 295 K.

From the ideal gas law we can determine the number of moles that the 2.25 L represent.

From there we will use the stoichiometry of the reaction to determine the moles of glucose which knowing the molar mass can be converted to mass.

PV = nRT    ⇒ n = PV/RT

n= 1 atm x 2.25 L / ( 0.08205 Latm/kmol x 295 K ) =0.093 mol CO₂

Moles glucose required:

0.093 mol CO₂  x  ( 1 mol C₆H₁₂O₆   / 2 mol CO₂ ) =  0.046 mol C₆H₁₂O₆

The molar mass of glucose is 180.16 g/mol, then the mass required is

0.046 mol x 180.16 g/mol = 8.37 g

5 0
3 years ago
A binary compound created by reaction of bismuth and an unknown element E contains 52.07% Bi and 47.93% E by mass. If the formul
yulyashka [42]

Answer:

Atomic mass of E is 128.24

Explanation:

  • The percentage composition by mass of an element in a compound is given by dividing the mass of the element by the total mass of the compound and expressing it as a percentage.
  • In this case; the compound Bi₂E₃

Percentage composition of bismuth = 52.07%

Percentage composition of E = 47.93%

Mass Bismuth in the compound is (2×208.9804) = 417.96 g

Therefore,

To calculate the atomic mass of E

52.07% = 417.96 g

47.93% = ?

            = (47.93 × 417.96 ) ÷ 52.07 %

            = 384.729

         E₃ = 384.729

Therefore; E = 384.729 ÷ 3

                     = 128.24  

The atomic mass of E is 128.24

6 0
3 years ago
Other questions:
  • HURRY PLS
    11·2 answers
  • ryan wants to identify an element. which piece of information would best help ryan identify the element? a. how many neutrons th
    10·2 answers
  • In addition to NF3, two other fluoro derivatives of nitrogen are known: N2F4 and N2F2. What shapes do you predict for these two
    7·1 answer
  • What is the chemical formula for the compound formed between chromium(III) and the bromate ion?
    11·1 answer
  • A 0.3423 g sample of pentane, C5H12, was burned in a bomb calorimeter. The temperature of the calorimeter and the 1.000kg of wat
    7·1 answer
  • What is a property of a substance? why are properties important? Explain your answer
    12·1 answer
  • 4 Compare and contrast the reactants and products in the two combustion
    8·1 answer
  • Convert 7.8 moles of carbon tetrafluoride into grams.
    14·1 answer
  • What happens when warm air rises? (5 points)
    6·2 answers
  • What are the three major branches of natural science?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!