Answer:
The required diameter of the fuse wire should be 0.0383 cm to limit the current to 0.53 A with current density of 459 A/cm²
.
Explanation:
We are given current density of 459 A/cm² and we want to limit the current to 0.53 A in a fuse wire. We are asked to find the corresponding diameter of the fuse wire.
Recall that current density is given by
j = I/A
where I is the current flowing through the wire and A is the area of the wire
A = πr²
but r = d/2 so
A = π(d/2)²
A = πd²/4
so the equation of current density becomes
j = I/πd²/4
j = 4I/πd²
Re-arrange the equation for d
d² = 4I/jπ
d = √4I/jπ
d = √(4*0.53)/(459π)
d = 0.0383 cm
Therefore, the required diameter of the fuse wire should be 0.0383 cm to limit the current to 0.53 A with current density of 459 A/cm²
.
Answer:
The second classmate is right.
Explanation:
The height of first summit provides the potential energy it will use to climb the following ones.
Ep = m * g * h
Where
m: mass
g: acceleration of gravity
h: height
When the train goes downwards the potential energy is converted into kinetic energy (manifested as speed) and when it climbs it consumes its kinetical energy. As long as no summit is taller than the first the train should have enough energy to climb them.
Also it must be noted that friction also consumes energy, and if the track is too lomg all the energy might be consumed by it.
Answer:
Depression, and health problems
Answer & Explanation:
(a) Frequency of 2Hz is applied to a sampler/zero-order hold combination
The sampling rate is 10Hz
List of all the frequencies present in the output that are less than 50Hz.
Adding:
fs + fm = 10 + 2
= 12 Hz
2fs + fm = 2 * 10 + 2
= 22 Hz
3fs + fm = 3 * 10 + 2
= 32 Hz
4fs + fm = 4 * 10 + 2
= 42 Hz
Subtracting:
fs - fm = 10 - 2
= 8 Hz
2fs - fm = 2 * 10 - 2
= 18 Hz
3fs - fm = 3 * 10 - 2
= 28 Hz
4fs - fm = 4 * 10 - 2
= 38 Hz
5fs - fm = 5 * 10 - 2
= 48 Hz
(b) Frequency of 8Hz is applied to a sampler/zero-order hold combination
The sampling rate is 10Hz
List of all the frequencies present in the output that are less than 50Hz.
Adding:
fs + fm = 10 + 8
= 18 Hz
2fs + fm = 2 * 10 + 8
= 28 Hz
3fs + fm = 3 * 10 + 8
= 38 Hz
Subtracting:
fs - fm = 10 - 8
= 2 Hz
2fs - fm = 2 * 10 - 8
= 12 Hz
3fs - fm = 3 * 10 - 8
= 22 Hz
4fs - fm = 4 * 10 - 8
= 32 Hz
5fs - fm = 5 * 10 - 8
= 42 Hz
