Answer:
Because he is the man who found the concept on input process and output theory.
Explanation:
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Answer:
C++ code:
#include<iostream>
using namespace std;
void sort(int al[30], int l)
{
//we use insertion sort to sort the array.
int p,q,k;
for(q=1;q<l;q++) //starting from the 2nd item of the array.
{
k= al[q]; //taking qth item as key value.
p=q-1;
while(p>=0 && al[p]>k)
{
al[p+1]=al[p]; //all items those are greaer than al[q] are shifted //to right.
p=p-1;
}
al[p+1]=k;
}
}
int main()
{
int p,l, arrl[30];
cout<<"Enter the number of items in your array: ";
cin>>l;
cout<<endl;
cout<<"Enter your "<<l<<" items"<<endl;
for(p=0;p<l;p++)
{
cin>>arrl[p];
}
sort(arrl, l); //call function sort() to sort the array.
cout<<"The array after sorting: ";
for(p=0;p<l;p++)
{
cout<<arrl[p]<<" ";
}
cout<<endl;
cout<<"The smallest item is: ";
cout<<arrl[0]<<endl;
cout<<"The middle item is: ";
cout<<arrl[l/2]<<endl;
cout<<"The biggest item is: ";
cout<<arrl[l-1]<<endl;
}
Output is given as image.
Answer:
Follows are the explanation of the choices:
Explanation:
Following are the Pseudocode for selection sort:
for j = 0 to k-1 do:
SS = i
For l = i + 1 to k-1 do:
If X(l) < X(SS)
SS= l
End-If
End-For
T = X(j)
X(j) = X(SS)
X(SS) = T
End-For
Following are the description of Loop invariants:
The subarray A[1..j−1] includes the lowest of the j−1 components, ordered into a non-decreasing order, only at beginning of the iteration of its outer for loop.
A[min] is the least amount in subarray A[j.. l−1] only at beginning of the each loop-inner iterations.
Following are the explanation for third question:
Throughout the final step, two elements were left to evaluate their algorithm. Its smaller in A[k-1] would be placed as well as the larger in A[k]. One last is the large and medium component of its sequence because most and the last two components an outer loop invariant has been filtered by the previous version. When we do this n times, its end is a repetitive, one element-sorting phase.
Following is the description of choosing best-case and worst-case in run- time:
The body the if has never been activated whenever the best case time is the list is resolved. This number of transactions are especially in comparison also as a procedure, that will be (n-1)(((n+2)/2)+4).
A structure iterator at every point in the worst case that array is reversed, that doubles its sequence of iterations in the inner loop, that is:(n−1)(n+6) Since both of them take timeΘ(n2).
b serves as food for the yeast
Answer:
The answer to the following blank is Theme.
Explanation:
To change themes in powerpoint:
- Firstly, click on DESIGN tab then, click in the Themes group.
- Then, choose one of the following themes.
- Then, under Custom, choose the custom theme to apply.
- Then, under Office, click the built-in themes and apply. If users goal is display the little to no color in the user's presentations then, apply the Office Theme.
- After all, click the Browse for Themes, and then locate and then click the theme.
