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2 years ago

PLEASE if u see this stop to help

Mathematics

1 answer:

ale4655 [162]2 years ago

5 0

Answer:

no you

Step-by-step explanation:!!!!!!

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PLEASE HELP FAST! Solve for Y in the following system of equations!

victus00 [196]

Answer:

B.) 3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

x - y = -1

3x + 5y = 21

Step 2: Rewrite Systems

x - y = -1

Add y to both sides: x = y - 1

Step 3: Redefine Systems

x = y - 1

3x + 5y = 21

Step 4: Solve for y

Substitution

Substitute in x: 3(y - 1) + 5y = 21
Distribute 3: 3y - 3 + 5y = 21
Combine like terms: 8y - 3 = 21
Add 3 to both sides: 8y = 24
Divide 8 on both sides: y = 3

7 0

3 years ago

B-3+4b=34 Solve equation

daser333 [38]

Answer:

b = 7.4

Step-by-step explanation:

b - 3 + 4b = 34

combine like terms:

5b - 3 = 34

5b = 37

divide by 5:

b = 7.4

3 0

3 years ago

Read 2 more answers

Please solve!! solve for y 3x-y=16 Will name the Brainliest!!

algol [13]

Answer:

y= 5.333

Step-by-step explanation:

4 0

3 years ago

Integrate G(x,y,z)equalsz over the parabolic cylinder yequalszsquared, 0less than or equalsxless than or equals2, 0less than

yKpoI14uk [10]

I gather you're supposed to compute the integral of $G(x,y,z)=z$ over a surface $S$ that is the part of the parabolic cylinder $y=z^2$ with $0\le x\le2$ and $0\le z\le\frac{\sqrt{15}}2$ .

We can parameterize $S$ by

$\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k$

with the given constraints on $x$ and $z$ . Take the normal vector to $S$ to be

$\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k$

so that the surface element is

$\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz$

Then in the integral, we have

$\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}$

5 0

3 years ago

Is the expression x3•x3•x3 equivalent to x3•3•3? Why or why not? Explain your reasoning.

devlian [24]

no they are different

if Base are equal power are added

like wise in first expressions power are added

but in second expressions cube of three is written as x to the power.

so they are not equal

3 0

3 years ago