So 7 is greater I am not smart I am just trying to answers some question
Answer:
12x^2+2x+7
Step-by-step explanation:
Distribute the Negative Sign:
=4x^2+6+7+−1(−8x^2−2x+6)
=4x^2+6+7+−1(−8x^2)+−1(−2x)+(−1)(6)
=4x^2+6+7+8x^2+2x+−6
Combine Like Terms:
=4x^2+6+7+8x^2+2x+−6
=(4x^2+8x^2)+(2x)+(6+7+−6)
=12x^2+2x+7
B = 26in, c = 40in
a^2 = 26^2 + 40^2
= 2276 (square root it)
a = 2root569 // 47.7in
Answer:
ℝ - {(-2/3),(3/2)}
Step-by-step explanation:
We want the domain of f(g(x)). So, firstly, we have to find the domain for g(x) and, then, for f(g(x)).
- Domain of g(x): Since the expression is a fracion, we must exclude the values of x that make null the denominator. Hence,

- Domain of f(g(x)): We'll find its expression:

Now, once again, we have to exclude the values of x that make the denominator equals to zero. Thus,

Lastly, we may write the domanin of f(g(x)):
![D(f(g(x)) = \left]-\infty,-\dfrac{2}{3}\right[\cup\left]-\dfrac{2}{3},\dfrac{3}{2}\right[\cup\left]\dfrac{3}{2},\infty\right[](https://tex.z-dn.net/?f=D%28f%28g%28x%29%29%20%3D%20%5Cleft%5D-%5Cinfty%2C-%5Cdfrac%7B2%7D%7B3%7D%5Cright%5B%5Ccup%5Cleft%5D-%5Cdfrac%7B2%7D%7B3%7D%2C%5Cdfrac%7B3%7D%7B2%7D%5Cright%5B%5Ccup%5Cleft%5D%5Cdfrac%7B3%7D%7B2%7D%2C%5Cinfty%5Cright%5B)
or, just writing in a shorter way:
