What’s the commutative steps to multiply 3 times 10 cubed and 2 times 10 to the 4th power

Solve. 15 − 6(x + 1) = 12 Help nowwwww

Gekata [30.6K]

Answer:

Your answer would be 2

Step-by-step explanation:

15 - 6(x+1) =12

15- 6*x +6*1 = 12

15 - 6x + 6 = 12

15 - 6 + 6x = 12

9 + 6x = 12

9 - 9 + 6x = 12 - 9

6x = 3

x = 2

5 0

3 years ago

Convert 0.45 to a percent. Remember to add the percent sign. 0.45% 4.5% 45% 50%

notka56 [123]

45% is the answer to this question

3 0

3 years ago

A bicycle is originally priced at $80 the store owner gives a discount in the bicycle is know priced at $60 enter the percent ma

Roman55 [17]

Answer:

25%

Step-by-step explanation:

Since we know that the markdown is $20 by subtracting 80-60 , we find out what percent of 20 is 80. To do that you do 20/80, which is 0.25, or 25 percent.

5 0

3 years ago

Read 2 more answers

Suppose that the quarterly sales levels among health care information systems companies are approximately normally distributed w

cupoosta [38]

Answer:

The cutoff sales level is 10.7436 millions of dollars

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 12, \sigma = 1.2$

15th percentile:

X when Z has a pvalue of 0.15. So X when Z = -1.047.

$Z = \frac{X - \mu}{\sigma}$

$-1.047 = \frac{X - 12}{1.2}$

$X - 12 = -1.047*1.2$

$X = 10.7436$

The cutoff sales level is 10.7436 millions of dollars

6 0

3 years ago

Let X denote the data transfer time (ms) in a grid computing system (the time required for data transfer) between a "worker" com

My name is Ann [436]

Answer:

a. The value of alpha is 3.014 and the value of beta is 12.442

b. The probability that data transfer time exceeds 50ms is 0.238

c. The probability that data transfer time is between 50 and 75 ms is 0.176

Step-by-step explanation:

a. According to the given data we have that the mean and standard deviation of the random variable X are 37.5 ms and 21.6.

Therefore, E(X)=37.5 and V(X)=(21.6)∧2

To calculate alpha we would have to use the following formula:

alpha=E(X)∧2/V(X)

alpha=(37.5)∧2/21.6∧2

alpha=1,406.25 /466.56

alpha=3.014

To calculate beta we would have to use the following formula:

β= V(X) ∧2/E(X)

β=(21.6) ∧2/37.5

β=466.56 /37.5

β=12.442

b. E(X)=37.5 and V(X)=(21.6)∧2

Therefore, P(X>50)=1−P(X≤50)

Hence, To calculate the probability that data transfer time exceeds 50ms we use the following formula:

P(X>50)=1−P(X≤50)

=1−0.762

=0.238

The probability that data transfer time exceeds 50ms is 0.238

c. E(X)=37.5 and V(X)=(21.6)∧2

Therefore, P(50<X<75)=P(X<75)−P(X<50)

Hence, To calculate the probability that data transfer time is between 50 and 75 ms we use the following formula:

P(50<X<75)=P(X<75)−P(X<50)

=0.938−0.762

=0.176

The probability that data transfer time is between 50 and 75 ms is 0.176

6 0

3 years ago