When oxygen is found is peroxide, it has an oxidation number of -1.
The chemical formula of hydrogen peroxide is H2O2. We know that hydrogen always has +1 oxidation state until it forms metal hydrides. So in H2O2, the oxidation state ofhydrogen is +1.
Now, let oxidation state of oxygen be x. So,
2 * (+1) + 2*x = 0
2 + 2x = 0
2x = -2
x = -2 / 2
x = -1
Hence, the oxidation number of oxygen in peroxides is -1
<u>Answer:</u>
<em>4.5 L water we have in litres (L).</em>
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<u>Explanation:</u>

where
= Final T - Initial T
Q is the heat energy in calories
c is the specific heat capacity (for water 1.0 cal/(g℃))
m is the mass of water
Plugging in the values

So,
Volume of water = mass/density

=4.5 L (Answer)
Answer:
156.86 g / mol
Explanation:
We start from the molarity law
Cm = n / V
n = w / M
then
Cm = (w / M) / V
Cm = w / (M × V)
where:
Cm is the molarity
n number of moles
w a mass of the solute
M is the molar mass of the solute (which is needed)
V the volume of the solution in liters
Then the M can be calculated as following:
M = w / (Cm × V)
M = 100 / (0.75 × 0.85) = 156.86 g / mol