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Ganezh [65]
3 years ago
5

How can water and gravity work together to erode soil,sediment,and rock

Chemistry
2 answers:
Sunny_sXe [5.5K]3 years ago
6 0
Ever seen a waterfall ? what do you think happens when all that water slams into the ground below ? same as when you turn a hosepipe on a flowerbed.

also, there's hydraulic cracking where water gets into cracks and freezes, splitting rocks apart.

fast moving water can carry sediment and roll rocks along the bottom. if the water slows down, it drops the rocks and heavier sediment. if it floods a field, say, then drains away, the grass will also filter smaller particles out, or the water might evaporate and leave fine sediment behind.
Paul [167]3 years ago
6 0
Water and gravity work together to erode soil, sediment, and rock with the water loosening the dirt around it, allowing gravity to take action by "pushing" the resources down, letting it roll either slowly or quickly down the slope it may be on.

I hope you like this answer and have a good day! :D
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Is the force between protons in the nucleus attractive or repulsive
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Answer:

Inside the nucleus, the attractive strong nuclear force between protons outweighs the repulsive electromagnetic force and keeps the nucleus stable. Outside the nucleus, the electromagnetic force is stronger and protons repel each other.

Explanation:

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Answer:

Periods on the periodic table of elements

Explanation:

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1) The temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperatur
viva [34]

Answer:  The volume of the balloon when it is fully cooled by my refrigerator is 0.3 L

Explanation:

To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=0.5L\\T_1=220^oC=(220+273)K=493K\\V_2=?\\T_2=40^oC=(40+273)K=313K

Putting values in above equation, we get:

\frac{0.5}{493}=\frac{V_2}{313}\\\\V_2=0.3

Thus the volume of the balloon when it is fully cooled by my refrigerator is 0.3 L

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