<u>Answer:</u> Oxidation state of Arsenic in the given compound is +3 and that of oxygen is -2.
<u>Explanation:</u>
We are given a compound having formula 
and we need to find the oxidation state of all the atoms in this compound. There are 2 different atoms present in this : Arsenic and Oxygen
Oxidation state is the number which is assigned to an element in a compound which represents the number of electrons lost or gained by an atom in a compound.
Oxidation state of oxygen as -2 which is same always. Now, to calculate the oxidation state of Arsenic, we take the oxidation state of it be 'x'
As, there are two arsenic atoms and three oxygen atoms, then:
Hence, oxidation state of Arsenic in the given compound is +3 and that of oxygen is -2.
Answer:
It depends on the number of significant figures you are changing to
Explanation:
6.02×1023=6158.46
1 sig fig = 6000
2 sig fig = 6200
3 sig fig = 6160
4 sig fig = 6158
5 sig fig = 6158.5
6 sig fig = 6158.46
When solving significant figures you have to consider the number after each number like in the case of changing to two sig fig the number following one is five and when the number is up to or greater than five you add a value of one to the number before it. But in a case where the number is less than five you just leave it like that like in the case of changing to one sig fig
It's B) electrons, is the right answer
Number protons is what determines the element.
16 protons determines that the substance is sulphur.
The number of neutrons can vary according to the isotope. The mass number is the total count of neutrons and protons, so sulphur with a mass number of 34 has 34-16=18 neutrons.
32.065 is the weighted average of the atomic weights of different isotopes, so does not apply to a single isotope.
