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3 years ago

HELP ASAP PLZZZ!!! I would be Soo grateful

Mathematics

1 answer:

Dmitry [639]3 years ago

5 0

Answer:

31%

Step-by-step explanation:

3/10 is the same as 30%

If 30% of the students liked English and 61% of the students like math, the difference can be found by using subtraction.

61% - 30% = 31%

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N(n - 4) + n(n + 8) = n(n - 13) + n(n + 1) + 16

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N^2 - 4n + n^2 + 8n = n^2 - 13n + n^2 + n + 16
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-4n = -12n + 16
4n + 12n = 16
16 = 16
n = 1

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The ratio of lime juice to soy sauce in a salad dressing is 8: 9 .The total of both ingredients is 51 tablespoons . How many tab

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2 years ago

What is<br> is 1/4 + 9/10y -3/5y +7/8 written in simplest form?

Leviafan [203]

Answer:

Step-by-step explanation:

$\frac{1}{4}+\frac{9}{10}y - \frac{3}{5}y+\frac{7}{8}\\\\=\frac{1}{4}+\frac{7}{8}+\frac{9}{10}y-\frac{3}{5}y\\\\$

Combine like terms. 1/4 and 7/8 are like terms and LCD of 4 and 8 is 8

9/10y and -3/5y are like terms and LCD of 10 , 5 is 10

$= \frac{1*2}{4*2}+\frac{7}{8}+\frac{9}{10}y-\frac{3*2}{5*2}y\\\\=\frac{2}{8}+\frac{7}{8}+\frac{9}{10}y-\frac{6}{10}y\\\\=\frac{9}{8}+\frac{3}{10}y$

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2 years ago

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Math, area all that yummy stuff

lilavasa [31]

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Step-by-step explanation:

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2 years ago

A new phone system was installed last year to help reduce the expense of personal calls that were being made by employees. Befor

Leya [2.2K]

Using the normal distribution, it is found that there was a 0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 700, \sigma = 50$ .

The probability of a month having a PCE between $575 and $790 is the <u>p-value of Z when X = 790 subtracted by the p-value of Z when X = 575</u>, hence:

X = 790:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{790 - 700}{50}$

Z = 1.8

Z = 1.8 has a p-value of 0.9641.

X = 575:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{575 - 700}{50}$

Z = -2.5

Z = -2.5 has a p-value of 0.0062.

0.9641 - 0.0062 = 0.9579.

0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

More can be learned about the normal distribution at brainly.com/question/4079902

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3 0

1 year ago