Witch of the following questoons would you expect to see on an interest inventory
1 answer:
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Answer:
p_{f} = 6 m / s
Explanation:
We can solve this exercise using conservation of momentum. For this we define a system formed by the two balls, so that the forces during the collision have been intense and the moment is preserved
Initial instant. Before the crash
p₀ = m v +0
Final moment. Right after the crash
= (m + m) v_{f}
how the moment is preserved
p₀ = p_{f}
m v = 2 m v_{f}
v_{f} = v / 2
we calculate
v_{f} = 12/2
p_{f} = 6 m / s
The total work done of 0.018 joules is needed to move the charges apart and double the distance between them.
We have two electric charges q(A) = 1μc and q(B) = -2μc kept at a distance 0.5 meter apart.
We have to calculate much work is needed to move the charges apart and double the distance between them.
<h3>What s the formula to calculate the Potential Energy of a system of two charges (say 'q' and 'Q') separated by a distance 'r' ?</h3>The potential energy of the system of two charges separated by a distance is given by -
In order to solve this question, it is important to remember the work - energy theorem which states -
"The change in the energy of the body is equal to work done on it"
Hence, using this work -energy theorem in the question given to us we get -
In our case -
W = 0.018 joules
Hence, the total work done should be 0.018 joules.
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