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galben [10]
3 years ago
7

Witch of the following questoons would you expect to see on an interest inventory

Physics
1 answer:
Roman55 [17]3 years ago
3 0

Answer: Do you like science experiments ? 1)

Would You enjoy reading a fashion magazine? 2)

Explanation:

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Star X has an apparent magnitude of 1. Star Y has an apparent magnitude of 4. Both stars are in the same star cluster. Which sta
sashaice [31]

Answer:

Explanation:

From the given information:

Since both stars are in the same cluster, the magnitude and luminosity relationship can be calculated as:

m_1 - m_2 = -2.5 log _{10} (\dfrac{L_1}{L_2})

Given that;

m_1 = 1 and

m_2 = 4

Therefore,

1 - 4 = -2.5 log _{10} ( \dfrac{L_1}{L_2})

3 = -2.5 log _{10} ( \dfrac{L_1}{L_2})

Making \dfrac{L_1}{L_2} the subject of the formula:

\implies \dfrac{L_1}{L_2}= 10^{(\dfrac{3}{2.5})}

=15.84

≅ 16

Hence, we can conclude that star X is more luminous by a factor of 16

7 0
2 years ago
In some employment situations, not all personnel can immediately evacuate a work area per the EAP. It may be that some equipment
Semmy [17]
These personnel are referred to as wardens. <span>They may also be responsible for checking offices, bathrooms, and other spaces before being the last person to exit an area. They might also be tasked with ensuring that fire doors are closed when exiting. </span>
3 0
3 years ago
A thin layer of oil of refractive index 1.22 is spread on the surface of water (n = 1.33), If the thickness of the oil is 275 nm
ANTONII [103]

Answer:

6.71×10⁻⁷ m

Explanation:

Using thin film constructive interference formula as:

<u>2×n×t = m×λ</u>

Where,

n is the refractive index of the refracted surface

t is the thickness of the surface

λ is the wavelength

If m =1

Then,

2×n×t = λ

Given that refractive index pf the oil is 1.22

Thickness of the oil = 275 nm

Also, 1 nm = 10⁻⁹ m

Thickness = 275×10⁻⁹ m

So,

Wavelength is :

<u>λ= 2×n×t = 2× 1.22 × 275×10⁻⁹ m = 6.71×10⁻⁷ m</u>

8 0
3 years ago
An Airbus A380 airliner can takeoff when its speed reaches 80 m/s. Suppose its engines together can produce an acceleration of 3
Tomtit [17]

Answer:

(a). The time is 26.67 sec.

(b). The distance traveled during this period is 1066.9 m.

Explanation:

Given that,

Speed = 80 m/s

Acceleration = 3 m/s

Initial velocity = 0

(a). We need to calculate the time

Using equation of motion

v = u+at

t = \dfrac{v-u}{a}

Put the value into the formula

t = \dfrac{80-0}{3}

t =26.67\ sec

The time is 26.67 sec.

(b). We need to calculate the distance traveled during this period

Using equation of motion

s = ut+\dfrac{1}{2}at^2

s = 0+\dfrac{1}{2}\times3\times(26.67)^2

s =1066.9\ m

The distance traveled during this period is 1066.9 m.

Hence, This is the required solution.

7 0
2 years ago
Consider a river flowing toward a lake at an average velocity of 3 m/s at a rate of 590 m3/s at a location 90 m above the lake s
Norma-Jean [14]

Explanation:

Given data

Velocity v=3 m/s

Water volume flow rate V=590 m³/s

Water elevation z=90 m

Water density p=1000 kg/m³

First we need to determine the energy per unit mass

So

e_{mech:}=e_{kine:}+e_{potent:}\\e_{mech:}=e_{potent:}\\e_{mech:}=gz\\e_{mech:}=9.81m/s*90m\\e_{mech:}=882.9J/kg\\or\\e_{mech:}=0.8829kJ/kg

Now the power generation potential is:

\\W=m.e_{mech:}\\where\\m=pV_{volume}\\So\\W=pV_{volume}e_{mech:}\\W=1000kg/m^{3}*590m^{3}/s*882.9j/kg\\W=5.21*10^{8}W\\or\\W=520911kW\\or\\W=521MW

8 0
2 years ago
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