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2 years ago

The inductance in the drawing has a value of L = 9.4 mH. What is the resonant frequency f0 of this circuit?

Physics

1 answer:

yuradex [85]2 years ago

4 0

Answer:

The resonant frequency of this circuit is 1190.91 Hz.

Explanation:

Given that,

Inductance, $L=9.4\ mH=9.4\times 10^{-3}\ H$

Resistance, R = 150 ohms

Capacitance, $C=1.9\ \mu F=1.9\times 10^{-6}\ C$

At resonance, the capacitive reactance is equal to the inductive reactance such that,

$X_C=X_L$

$2\pi f_o L=\dfrac{1}{2\pi f_oC}$

f is the resonant frequency of this circuit

$f_o=\dfrac{1}{2\pi \sqrt{LC}}$

$f_o=\dfrac{1}{2\pi \sqrt{9.4\times 10^{-3}\times 1.9\times 10^{-6}}}$

$f_o=1190.91\ Hz$

So, the resonant frequency of this circuit is 1190.91 Hz. Hence, this is the required solution.

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2 years ago

What is the electric potential energy of an electron at the negative end of the cable, relative to the positive end of the cable

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Answer:

Electric potential energy at the negative terminal: $1.92\cdot 10^{-18}J$

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The particle is an electron, so its charge is

$q=-1.60\cdot 10^{-19}C$

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$V_+=0V$

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$V_-=-12 V$

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$\Delta V = -12-0 = -12 V$

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$\Delta U = (-1.6\cdot 10^{-19})(-12)=1.92\cdot 10^{-18}J$

This means that the electron when it is at the negative terminal has $1.92\cdot 10^{-18}J$ of energy more than when it is at the positive terminal.

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3 years ago

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista

lions [1.4K]

The answer is 60 mph.

The speed (v) is distance (d) per time (t): v = d/t

Car A:
v1 = ?
t1 = 2 h
d1 = ?
___
v1 = d1/t1
d1 = v1 * t1

Car B:
v2 = ?
t2 = 1.5 h
d2 = ?
___
v2 = d2/t2
d2 = v2 * t2

Two cars traveled equal distances:
d1 = d2
v1 * t1 = v2 * t2

Car B traveled 15 mph faster than Car A:
v2 = v1 + 15

v1 * t1 = v2 * t2
v2 = v1 + 15
________
v1 * 2 = (v1 + 15) * 1.5
2v1 = 1.5v1 + 22.5
2v1 - 1.5v1 = 22.5
0.5v1 = 22.5
v1 = 22.5/0.5
v1 = 45 mph

v2 = v1 + 15
v2 = 45 + 15
v2 = 60 mph

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2 years ago