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FromTheMoon [43]
3 years ago
6

The inductance in the drawing has a value of L = 9.4 mH. What is the resonant frequency f0 of this circuit?

Physics
1 answer:
yuradex [85]3 years ago
4 0

Answer:

The resonant frequency of this circuit is 1190.91 Hz.

Explanation:

Given that,

Inductance, L=9.4\ mH=9.4\times 10^{-3}\ H

Resistance, R = 150 ohms

Capacitance, C=1.9\ \mu F=1.9\times 10^{-6}\ C

At resonance, the capacitive reactance is equal to the inductive reactance such that,

X_C=X_L    

2\pi f_o L=\dfrac{1}{2\pi f_oC}

f is the resonant frequency of this circuit  

f_o=\dfrac{1}{2\pi \sqrt{LC}}

f_o=\dfrac{1}{2\pi \sqrt{9.4\times 10^{-3}\times 1.9\times 10^{-6}}}

f_o=1190.91\ Hz

So, the resonant frequency of this circuit is 1190.91 Hz. Hence, this is the required solution.

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What ocean depth would the volume of an aluminium sphere be reduced by 0.10%
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Answer:

6400 m

Explanation:

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Since ρ is changing by very little, we can say:

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E = 69 GPa = 69×10⁹ Pa

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If we assume seawater density is constant at 1027 kg/m³, then:

ρgh = P

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h = 6350 m

Rounded to two sig-figs, the ocean depth at which the sphere's volume is reduced by 0.10% is approximately 6400 m.

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