Answer:
The resonant frequency of this circuit is 1190.91 Hz.
Explanation:
Given that,
Inductance,
Resistance, R = 150 ohms
Capacitance,
At resonance, the capacitive reactance is equal to the inductive reactance such that,
f is the resonant frequency of this circuit
So, the resonant frequency of this circuit is 1190.91 Hz. Hence, this is the required solution.
Answer:
Less than 18000N
Explanation:
Given
This question will be answered using Newton's third law.
Understanding this law, it implies that reaction force is equal and opposite to the force exerted.
This implies that;
If the force exerted on the ball is 18000N
the force exerted is -18000N
So, the option that answers the question is less than 18000N because -18000N < 18000N
Answer:
Choice a. , assuming that the skating rink is level.
Explanation:
<h3>Net force in the horizontal direction</h3>There are two horizontal forces acting on the boy:
The boy should be moving in the direction of the pull of his friend. The frictions on this boy should oppose that motion. Therefore, the frictions on the boy would be in the opposite direction of the pull of his friend.
The net force in the horizontal direction should then be the difference between the pull of the friend, and the friction on this boy.
.
The net force on this boy should be zero in the vertical direction. Consider Newton's Second Law of motion. The net force on an object is proportional to its acceleration. In this question, the net force on this boy in the vertical direction should be proportional to the vertical acceleration of this boy.
However, because (by assumption) the ice rink is level, the boy has no motion in the vertical direction. His vertical acceleration will be zero. As a result, the net force on him should also be zero in the vertical direction.
<h3>Net force</h3>Therefore, the (combined) net force on this boy would be:
.
Answer:
The magnetic field strength needed is 1.619 T
Explanation:
Given;
Number of turns, N = 485-turn
Radius of coil, r = 0.130 m
time of revolution, t = 4.17 ms = 0.00417 s
average induced emf, V = 10,000 V.
Average induced emf is given as;
V = -ΔФ/Δt
where;
ΔФ is change in flux
Δt is change in time
ΔФ
where;
N is the number of turns
B is the magnetic field strength
A is the area of the coil = πr²
θ is the angle of inclination of the coil and the magnetic field,
V = NBACos0/t
V = NBA/t
B = (Vt)/NA
B = (10,000 x 0.00417) / (485 x π x 0.13²)
B =1.619 T
Thus, the magnetic field strength needed is 1.619 T
Answer:
Explanation:
Given that.
Force acting on the particle,
Position of the particle,
To find,
(a) Torque on the particle about the origin.
(b) The angle between the directions of r and F
Solution,
(a) Torque acting on the particle is a scalar quantity. It is given by the cross product of force and position. It is given by :
So, the torque on the particle about the origin is (32 N-m).
(b) Magnitude of r,
Magnitude of F,
Using dot product formula,
Therefore, this is the required solution.
Explanation:
hope this would be the right answer ..
