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Lubov Fominskaja [6]
4 years ago
6

Why one part of the earth's surface is arid and dry and a nearby part is lush and wet is explained by the term?

Physics
1 answer:
Darina [25.2K]4 years ago
8 0
The process that explains why one part of the earth's surface is arid and dry and a nearby part is lush and wet is areal differentiation. It is<span> an approach to geography that shows </span>the dependence of the distribution of physical and human phenomena and the relation  to each other from the physical location. Areal integration on the other hand is the approach that studies how places interact with each other.
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What is a meteorite??​
Fittoniya [83]

Answer:

a piece of rock or metal that has fallen to the earth's surface from outer space as a meteor. Over 90 per cent of meteorites are of rock while the remainder consist wholly or partly of iron and nickel

Explanation:

See above

3 0
3 years ago
How much work is done against gravity when lifting a 2-kg sack of groceries a distance of 2.5 meters?
Crazy boy [7]
W = F x d/x = (m x Ag) x h, therefore, mass (2kg x 9.8) x 2.5m = 49J
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3 years ago
Which form of energy body will possess when it is kept on the top of Hill
Oduvanchick [21]

Potential energy would be the answer


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3 0
3 years ago
Read 2 more answers
A negative velocity, approaching zero, represents a negative acceleration. True or False
ruslelena [56]

Answer:

False.

Explanation:

Lets assume our positive direction to the right (this reasoning works for any direction). A negative velocity would then be then directed to the left. If it varies as such that it aproaches to zero, it means that the variation is directed to the right, and that is where the direction of the acceleration must be pointing. In other words, its losing its velocity, so the acceleration must point opposite to the velocity. Then it means the acceleration is positive.

8 0
4 years ago
A ball is dropped from the top of a tower 40 m high. What is its velocity when it has covered 20 m? What would be its velocity w
stellarik [79]

Given :

Height from which ball is dropped , h = 40 m .

Acceleration due to gravity , g= 10 m/s² .

Initial velocity , u = 0 m/s .

To Find :

Velocity when ball covered 20 m and velocity when it hit the ground .

Solution :

Now , height when ball covered 20 m distance is , 40 - 20 = 20 m .

By equation of motion :

v^2=u^2+2gh\\\\v=\sqrt{2\times 10\times 20}\ m/s\\\\v=20\ m/s

Now , distance covered when body reaches ground is , 40 m .

Putting value h = 40 m in above equation , we get :

v=\sqrt{2\times 10\times 40}\ m/s\\\\v=20\sqrt{2}\ m/s

Hence , this is the required solution .

7 0
3 years ago
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