Solution :
Given :
Mass attached to the spring = 4 kg
Mass dropped = 6 kg
Force constant = 100 N/m
Initial amplitude = 2 m
Therefore,
a). 
= 10 m/s
Final velocity, v at equilibrium position, v = 5 m/s
Now, 
A' = amplitude = 1.4142 m
b). 
m' = 2m
Hence, 
c). 
Therefore, factor
Thus, the energy will change half times as the result of the collision.
The higher you go the more potential energy there is, and the lower it is the more kinetic energy there is, so the more kinetic energy there is the higher the ball will bounce.
Gravitational field exists in
the space surrounding a charged particle and exerts a force on other charged
particles. Gravitational waves are ripples of waves travelling outward from the
source. The more massive the orbit of two bodies, the more it emits
gravitational wave. And everything around it that is near within the wave
experiences a ‘pull’ toward the orbiting bodies.
First, we determine the volume of the trunk by finding
first the radius from the circumference through the equation,
<span> C
= 2πr</span>
<span> r
= C/2π</span>
Substituting the known values,
<span> r
= 4.5/2π = 0.716 m</span>
Then, we calculate for the volume through the equation,
<span> V
= πr2h</span>
<span> V
= π(0.716 m)2(8m) = 12.9 m3</span>
Multiplying the calculated value to the density will give
the mass as,
<span> Mass
= (12.9 m3)(752 kg/m3) = <span>9699.36 kg</span></span>
