Answer:
42.9 μF
Explanation:
V = 3.50 V, Q = 150 μC
C = Q/V = 150/3.50 μF = 42.9 μF
Answer:
7.468 kN
Explanation:
Here the force of 7468 Newton is given.
Some of the prefixes of the SI units are
kilo = 10³
Mega = 10⁶
Giga = 10⁹
The number is 7468.0
Here, the only solution where the number of significant figures is kilo
1 kilonewton = 1000 Newton
So 7468 N = 7.468 kN
How it is used in manufacturing reactivity
Answer:
18301.4Kg
Explanation:
Step 1:
Data obtained from the question. This include the following:
Mass 1 (M1) = 0.512Kg
Mass 2 (M2) =..?
Distance apart (r) = 0.0250m
Force (F) = 0.001N
Gravitational force constant (G) = 6.67x10^-11Nm²/Kg²
Step 2:
Determination of the mass, M2 needed to create a force of 0.001N.
This can be obtained as follow:
F = GM1M2/r²
0.001 = 6.67x10^-11 x 0.512 xM2/0.025²
Cross multiply
6.67x10^-11 x 0.512 xM2 = 0.001x0.025²
Divide both side by 6.67x10^-11 x 0.512
M2 = (0.001x0.025²)/(6.67x10^-11x0.512)
M2 = 18301.4Kg
Therefore, a mass of 18301.4Kg is needed
