I put the solution on the paper
It has 15 things affghhjj ibhcff
Answer: 8
Step-by-step explanation: if you count the angels and the sides then you'll get the answer 8..
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Which set of ordered pairs represents a function? {(2, –2), (1, 5), (–2, 2), (1, –3), (8, –1)} {(3, –1), (7, 1), (–6, –1), (9, 1
ra1l [238]
A function can't have x repeating any of the same number twice for example the first one (2, -2), (1, 5), (-2, 2), (1,-3), (8,-1) you have two 1's (1,5) and (1,-3) the x is the first number. Now a function can have the same y value. So your answer is (3, -1), (7,1), (-6,-1), (9,1), and (2,-1) you have to have all different x values in order for it to be a function. Hope that helps.
