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Mrrafil [7]
2 years ago
8

What is the first correct step to solve this system of equations4x-3y=-102x 3y=4?

Mathematics
1 answer:
kherson [118]2 years ago
4 0
You first need to isolate either x or y. since in one formula has both x and y in it and there is one with only y, you should solve the smaller one first then plug and chug
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Janice is building a fence around a portion of her rectangular yard. The length of yard she will enclose is x, and the width is
Kipish [7]

We are given

length of rectangular yard is x

so, L=x

width of rectangular yard is

so, W=2x^2-98x+5

We are given

the length of the enclosed yard is 50 feet

so, we get

L=x=50

now, we can plug x=50 and then we can find width

W=2(50)^2-98(50)+5

W=105

now, we can find total fencing length

so, total fencing length is

=2L+2W

now, we can plug values

=2\times 50+2\times 105

=310feet

now, we are given

the cost of fencing is $13 per foot

so,

total cost = (cost of fencing)*(total fencing length)

we can plug values

C=13\times 310

C=4030

So, Janice will spend $4030.........Answer

6 0
3 years ago
Big Red Gymnastics Academy charges an initial fee of $200 to rent its gym for birthday parties. The academy then charges an addi
Svetach [21]

Answer:y-200=75x

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
A quantity with an initial value of 3700 decays exponentially at a rate of 6% every 5
SSSSS [86.1K]

Answer:

2369.86

Step-by-step explanation:

f(36)=3700(1−0.06) ^36/5

2369.857704098921

4 0
1 year ago
. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte
Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}

4 0
2 years ago
Benny thinks of a number, subtracts 18 from it, and divides the difference by 3, the result is (-4). What is the number?
White raven [17]

Answer:

n=6

Step-by-step explanation:

(n-18)/3 = -4

multiply by 3

n-18 = -12

add 18

n = 6

7 0
3 years ago
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