The equation of the tangent line at x=1 can be written in point-slope form as
... L(x) = f'(1)(x -1) +f(1)
The derivative is ...
... f'(x) = 4x^3 +4x
so the slope of the tangent line is f'(1) = 4+4 = 8.
The value of the function at x=1 is
... f(1) = 1^4 +2·1^2 = 3
So, your linearization is ...
... L(x) = 8(x -1) +3
or
... L(x) = 8x -5
Answer:
-21 3/5
Step-by-step explanation:
May i have brainliest
Answer:
18,480
Step-by-step explanation:
Ⓗⓘ ⓣⓗⓔⓡⓔ
Well, first, you would fine how much she put in the bank in the first place!
250,000-96,000=154,000
Then you would do 154,000*0.02 to find how much interest is charged per month.
154,000*0.02=3080
Finally, you would multiply 3080 by 6 {because you need to account for all of the months}.
3080*6=18,480
(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥
Answer:
1/9
Step-by-step explanation:
3^-2
0.111111...
1/9
The answer is 0.45 recurring. Hope this helped or helps you. :)
