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andriy [413]
4 years ago
15

What is 2×(-5)-(-8)=? cause I need the answer for something rlly bad

Mathematics
1 answer:
shepuryov [24]4 years ago
6 0
The answer to this is -2
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Work out (3.6 times 10^-5) divided by (1.8 times 10^2) Give your answer in simplest form.
romanna [79]

Answer:

( 3.6 × 10 ^-5 ) ÷ ( 1.8 × 10² ) = 2 × 10^-7

4 0
3 years ago
Describe the association you see between the number of quartz purchased and the price per quart. Explain.
Scilla [17]
Number of quartz implies how much quartz you want .It can be 2 , 3 a hundred, a thousand..(Quantitative).

the price per quart is the price of a single quartz that is only for 1 piece (only)
8 0
3 years ago
Naomi has earned $54 mowing lawn the past few days. She worked 2 1/2 hours yesterday and 4 1/4 hours today. If Naomi is paid the
marysya [2.9K]
The answer is $8 per hour. To get this you add the 2 1/2 and 4 1/4 and that equals 6 3/4 or 6.75. You then divide 54 by 6.75 and you get 8.
8 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
The ratio of boys to girls in a class is 4:5 what fraction of the class is boys and what fraction of the class is girls
ale4655 [162]
First, let's start off with the information we already have. Since the ratio is 4 boys to 5 girls, there has to be a minimum of 9 students (4 being boys and 5 being girls).

9 will be the denominator of both of our fractions since the boys and girls are in the same class.

The fraction of boys in the class is 4/9 (since there are 4 boys to 5 girls in a class of 9, we would write 4 over 9) and the fraction of girls in the class is 5/9.

This is a simplified version of the fractions. If this is a multiple-answer question and 4/9 and 5/9 are not up there, try multiplying the fractions with different numbers and see what fractions will be correct. 

But either way, 4/9 and 5/9 are correct :)

7 0
3 years ago
Read 2 more answers
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