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Tresset [83]
3 years ago
11

Do a stretched spring and a box on a high shelf both have potential energy why or why not explain you answer?

Physics
1 answer:
Kipish [7]3 years ago
3 0
The correct answer to this question is "Yes." A stretched spring and a box on a high shelf both have potential energy. P<span>otential energy is energy reserved to do work. </span><span>Potential energy</span><span> </span><span>stored as a result of deformation of an elastic object, such as the stretching of a</span><span> </span><span>spring</span><span>. It is equal to the work done to stretch the</span><span> </span><span>spring</span><span>, which depends upon the</span><span> </span><span>spring </span><span>constant k as well as the distance stretched.</span>
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The SI system uses three base units. Is this true or false?
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8 0
1 year ago
Read 2 more answers
When a condenser discharges electricity, the instantaneous rate of change of the voltage is proportional to the voltage in the c
e-lub [12.9K]

Answer:

460.52 s

Explanation:

Since the instantaneous rate of change of the voltage is proportional to the voltage in the condenser, we have that

dV/dt ∝ V

dV/dt = kV

separating the variables, we have

dV/V = kdt

integrating both sides, we have

∫dV/V = ∫kdt

㏑(V/V₀) = kt

V/V₀ = e^{kt}

Since the instantaneous rate of change of the voltage is -0.01 of the voltage dV/dt = -0.01V

Since dV/dt = kV

-0.01V = kV

k = -0.01

So, V/V₀ = e^{-0.01t}

V = V₀e^{-0.01t}

Given that the voltage decreases by 90 %, we have that the remaining voltage (100 % - 90%)V₀ = 10%V₀ = 0.1V₀

So, V = 0.1V₀

Thus

V = V₀e^{-0.01t}

0.1V₀ = V₀e^{-0.01t}

0.1V₀/V₀ = e^{-0.01t}

0.1 = e^{-0.01t}

to find the time, t it takes the voltage to decrease by 90%, we taking natural logarithm of both sides, we have

㏑(0.01) = -0.01t

So, t = ㏑(0.01)/-0.01

t = -4.6052/-0.01

t = 460.52 s

3 0
3 years ago
The length of the track itself is 500m. The vehicles (each of mass 15kg) are dragged
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Answer:

W = 100000 J = 100 KJ

Explanation:

Here we will use the most basic and general formula of work, which is as follows:

W = Fd

where,

W = Work Done = ?

F = Force Required = 200 N

d = Length of Track = 500 m

Therefore,

W = (200\ N)(500\ m)\\

<u>W = 100000 J = 100 KJ</u>

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3 years ago
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B. Aluminum is possibly correct

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