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arsen [322]
2 years ago
8

10. A book has a mass of 400 g. The surface of the book in contact with a table has dimensions 0.10m x 0.20 m. The gravitational

field strength g is 10 N/kg. What is the pressure exerted on the table due to the book? A 0.08 N/m? B 8.0 N/m C 20 N/m2 D 200 N/m
Physics
1 answer:
morpeh [17]2 years ago
8 0

The pressure exerted on the table due to the book is 200 N/m².

The given parameters;

  • <em>mass of the book, m = 400 g = 0.4 kg</em>
  • <em>dimension of the table,  = 0.10m x 0.20 m.</em>
  • <em>gravitational field strength g =  10 N/kg.</em>

The area of the table is calculated as follows;

A = 0.1 x 0.2 = 0.02 m²

The pressure exerted on the table due to the book is calculated as follows;

P = \frac{F}{A}

where;

  • <em>F is the force of the book due to its weight</em>

<em />

P =\frac{F}{A} = \frac{mg}{A} = \frac{0.4 \times 10}{0.02} = 200 \ N/m^2

Thus, the pressure exerted on the table due to the book is 200 N/m².

Learn more here:brainly.com/question/21935783

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Answer: When 1.0kg of aluminium block is used, the final temperature of the mixture will be T = 36.2∘C

If 1.0kg copper block is used, T of the mixture will be = 17.4∘C

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Explanation:

H = mcΘ

heat lost by block = heat gained by water

m₁c₁Θ₁ = m₂c₂Θ₂ where m₁ is mass of aluminium, m₂ is mass of water, c₁ is cAluminium, c₂ is cWater, Θ₁ is temperature change for aluminium, Θ₂ is temperature change for water.

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<em>when 1.0kg of aluminium block is used, the final temperature of the mixture will be </em><em>T</em>

heat lost by block = heat gained by water

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<em>If 1.0kg copper block is used, T of the mixture will be</em>

heat lost by block = heat gained by water

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<em>If 100g (0.1kg) of ice at 0∘C is used, T will be</em>

<em>heat lost by block = heat gained by water + heat used in melting ice to form water at 0∘C</em>

heat used in melting 0.1kg of ice, H = ml, where l= 33600J/Kg

0.5*900*(200-T) = 0.1*4186*(T-0) + 0.1*33600J/Kg

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0.5*900*(200-T) = 0.025*4186*(T-0) + 0.025*33600J/Kg

90000 - 450T =  104.65T + 8400

104.65T + 450T = 90000 - 8400

554.65T = 81600

T = 81600/554.65 = 147.1∘C

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