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Nadusha1986 [10]
3 years ago
9

Solve the following system of equations Y=x^2+3 y=x+5

Mathematics
1 answer:
valina [46]3 years ago
4 0

Answer:

(2,7) and (-1,4)

Step-by-step explanation:

solve for the first variable in one of the equations then

substitute the result into the other equation.

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Determine the slope of the following graph.
evablogger [386]

Answer:

2/1 or 2

Step-by-step explanation:

if you find a spot were the line is line up with the boxes in the graph like at (-2,0) up 2 and right one you will see the line is lined up again and since slope is rise/run its 2/1 or 2

4 0
3 years ago
Hi please can you help me this is a new topic and I’m very confused
olchik [2.2K]

Answer: the large jar is cheaper

Step-by-step explanation:

If you divide the £1.54 by 440g and £1.26 by 340g, you'll find which one is cheaper per gram :

1.54/440 = 0.0035

1.26/340 = 0.0037

So, by comparing both prices/gram, you've found that the large jar is cheaper.

8 0
2 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
1 year ago
Anita had $400 in her savings account when she went to college. Her parents will add $200 to her account each month.
Stolb23 [73]
Anita's account had linear growth
Miguel's account had exponential growth.
Miguel's account grew faster because exponential growth is faster than linear growth
6 0
3 years ago
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What are the missing angle measure in a parallelogram rstu
hichkok12 [17]

The answer to the question is the second option.

6 0
2 years ago
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