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3 years ago

How to find x and round that answer to the nearest tenth

Mathematics

1 answer:

Tatiana [17]3 years ago

6 0

This is very weird. How to find x and round that answer to the nearest tenth,

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You roll a dice three times what is the probability that you roll an even number on the first roll, and odd on the second roll a

Dafna1 [17]

<h3>Answer:</h3>

D. 1/24

<h3>Step-by-step explanation:</h3>

Assuming the die is fair and the events are independent, the probability of the series of events is the product of the probabilities of the individual events.

p(even) = 3/6 = 1/2

p(odd) = 3/6 = 1/2

p(5) = 1/6

Then the joint probability is ...

.. (1/2)·(1/2)·(1/6) = 1/24

7 0

3 years ago

Using the "Part4Series.txt" time series

vekshin1

Answer:

idrk but use brainly it rly helps

Step-by-step explanation:

7 0

3 years ago

What is the value of the expression? 3.2(2.3)−4.8 Enter your answer in the box as a decimal.

iren2701 [21]

3.2(2.3) - 4.8

Simplify.

(3.2 × 2.3) - 4.8

Simplify.

(10.24) - 4.8

Simplify.

5.44

~Hope I helped!~

8 0

3 years ago

Read 2 more answers

Can someone find the sum?

viktelen [127]

X^2 + x + 1 + 3x^2 + 3x + 2. Just combine the like terms:

x^2 + 3x^2 + x + 3x + 1 + 2

4x^2 + 4x + 3. <--- the sum.

5 0

3 years ago

Read 2 more answers

According to the Stack Overflow Developers Survey of 20184, 25.8% of developers are students.The probability that a developer is

murzikaleks [220]

Answer:

0.0326 = 3.26% probability that she is a student.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Woman developer

Event B: Student

Probability that the developer is a woman:

7.4% of 25.8%(students).

76.4% of 100 - 25.8 = 74.2%(not students). So

$P(A) = 0.074*0.258 + 0.764*0.742 = 0.58598$

Student and woman developer.

7.4% of 25.8%(students), so

$P(A \cap B) = 0.074*0.258 = 0.019092$

If we encounter a woman developer, what is the probability that she is a student

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.019092}{0.58598} = 0.0326$

0.0326 = 3.26% probability that she is a student.

5 0

2 years ago