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3 years ago

Which of the following shows 27/54 written in Prime factored form to help in reducing the fraction to simplest form?

Mathematics

1 answer:

hammer [34]3 years ago

5 0

Because both numbers are divisible by 27, you can divide by nine to get $\frac{1}{2}$ .

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Expression equivalent to -2.5(4x-3)

e-lub [12.9K]

If you distribute, then you get -10x+7.5

Note how -2.5 times 4x = -10x and how -2.5 times -3 = 7.5

The idea is that you multiply the outer term (-2.5) by each term inside

6 0

3 years ago

Enzo’s mean score is 44. Zahra’s mean score is 38. The difference between the mean scores is about how many times the mean absol

konstantin123 [22]

The correct answer is 1.

4 0

3 years ago

I need help with shapes, can someone help me with this problem

posledela

Answer:

90%

Step-by-step explanation:

9/10's of the two rectangles are shaded and 9/10 = 90%

7 0

3 years ago

Read 2 more answers

(1.1/1.2: Interpolating polynomials) Say we want to find a polynomialf(x) ofdegree 3,f(x) =a0+a1x+a2x2+a3x3,satisfying some inte

Hunter-Best [27]

(a) If

f(x) = a₀ + a₁ x + a₂ x ² + a₃ x ³

then from the given conditions we get the system of equations,

f (-1) = a₀ - a₁ + a₂ - a₃ = -1

f (1) = a₀ + a₁ + a₂ + a₃ = 2

f (2) = a₀ + 2a₁ + 4a₂ + 8a₃ = 1

f (3) = a₀ + 3a₁ + 9a₂ + 27x ³ = 5

(b) Similarly, if

f(x) = a₀ + a₁ x + a₂ x ² + a₃ x ³

then

f'(x) = a₁ + 2a₂ x + 3a₃ x ²

so that the given conditions yield the system,

f (1) = a₀ + a₁ + a₂ + a₃ = 0

f' (1) = a₁ + 2a₂ + 3a₃ = 2

f (2) = a₀ + 2a₁ + 4a₂ + 27a₃ = 3

f' (2) = a₁ + 4a₂ + 12a₃ = -1

7 0

2 years ago

LK is tangent to circle J at point K. Circle J is shown. Line segment J K is a radius. Line segment K L is a tangent that inters

Evgen [1.6K]

Answer:

$(B)r=\dfrac{85}{12}$

Step-by-step explanation:

Given a circle centre J

Let the radius of the circle =r

LK is tangent to circle J at point K

From the diagram attached

LX=6
Radius, XJ=JK=r
LK=11

Theorem: The angle between a tangent and a radius is 90 degrees.

By the theorem above, Triangle JLK forms a right triangle with LJ as the hypotenuse.

Using Pythagoras Theorem:

$(6+r)^2=r^2+11^2\\(6+r)(6+r)=r^2+121\\36+6r+6r+r^2=r^2+121\\12r=121-36\\12r=85\\r=\dfrac{85}{12}$

The length of the radius, $r=\dfrac{85}{12}$

8 0

3 years ago

Read 2 more answers