Answer:
Mass = 2.7 g
Explanation:
Given data:
Number of moles of C₅H₁₂ = 0.9249 mol
Mass of water = ?
Solution:
Chemical equation:
C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O
Now we will compare the moles of water with pentane.
C₅H₁₂ : H₂O
1 : 6
0.9249 : 1/6×0.9249= 0.15 mol
Mass of water:
Mass = number of moles × molar mass
Mass = 0.15 mol × 18 g/mol
Mass = 2.7 g
The mass of NaCl needed for the reaction is 91.61 g
We'll begin by calculating the number of mole of F₂ that reacted.
- Gas constant (R) = 0.0821 atm.L/Kmol
PV = nRT
1.5 × 12 = n × 0.0821 × 280
18 = n × 22.988
Divide both side by 22.988
n = 18 / 22.988
n = 0.783 mole
Next, we shall determine the mole of NaCl needed for the reaction.
F₂ + 2NaCl —> Cl₂ + 2NaF
From the balanced equation above,
1 mole of F₂ reacted with 2 moles of NaCl.
Therefore,
0.783 mole F₂ will react with = 0.783 × 2 = 1.566 moles of NaCl.
Finally, we shall determine the mass of 1.566 moles of NaCl.
- Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Mass = mole × molar mass
Mass of NaCl = 1.566 × 58.5
Mass of NaCl = 91.61 g
Therefore, the mass of NaCl needed for the reaction is 91.61 g
Learn more about stiochoimetry: brainly.com/question/25830314
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