3 years ago

Find 1+ 2+ 3+ 4+ ... +50, the sum of the first 50 natural numbers. The sum is

Mathematics

1 answer:

SOVA2 [1]3 years ago

7 0

Step-by-step explanation:

First term(a) = 1

Common difference(d)=2-1=1

No.of term(n)=50

Sn=n÷2(n+1)=50÷2(50+1)=1275

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Answer:

$=27a^3b^3+54a^2b^2c+36abc^2+8c^3$

Step-by-step explanation:

$(3ab+2c)^3$

$=(3ab+2c)$ × $(3ab+2c)$ ×

$=(3ab+2c)(9a^2b^2+12abc+4c^2)$

$=(3ab)(9a^2b^2)+(3ab)(12abc)+(3ab)(4c^2)+(2c)(9a^2b^2)+(2c)(12abc)+(2c)(4c^2)$

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$=27a^3b^3+54a^2b^2c+36abc^2+8c^3$

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Indicate a general rule for the n th term of this sequence. 6a, 3a, 0, -3a, -6a, . . .

GrogVix [38]

Hello :
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a general rule for the n th term is : Un =U1+(n-1)d
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---

Mademuasel [1]

Answer:

Step-by-step explanation:

u keep multiplying see 2*2= 4*4=16*16=256*256=65536*65536= etc

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