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3 years ago

The answer to a subtraction problem

Mathematics

2 answers:

Ronch [10]3 years ago

7 0

Answer:

The answer in a subtraction problem is called the difference.

Step-by-step explanation:

goblinko [34]3 years ago

3 0

Hi there!

The answer to a subtraction problem is called rest or difference while the top thats being subtracted is called the minuend and the middle one is called the subtrahend.

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A study is performed in San Antonio to determine whether the average weekly grocery bill per five-person family in the town is s

bogdanovich [222]

Answer:

No, the sample evidence is not statistically significant (P-value = 0.125).

To reject the null hypothesis, the P-value has to be smaller than the significance level, so the significance level to reject the null hypothesis has to be 0.125 or higher.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average weekly grocery bill per five-person family in San Antonio is significantly different from the national average.

Then, the null and alternative hypothesis are:

$H_0: \mu=131\\\\H_a:\mu\neq 131$

The significance level is 0.05.

The sample has a size n=50.

The sample mean is M=133.474.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=11.193.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{11.193}{\sqrt{50}}=1.583$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{133.474-131}{1.583}=\dfrac{2.474}{1.583}=1.563$

The degrees of freedom for this sample size are:

$df=n-1=50-1=49$

This test is a two-tailed test, with 49 degrees of freedom and t=1.563, so the P-value for this test is calculated as (using a t-table):

$P-value=2\cdot P(t>1.563)=0.125$

As the P-value (0.125) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the average weekly grocery bill per five-person family in San Antonio is significantly different from the national average.

8 0

3 years ago

You cut off half of a strip of paper.Then you cut off half of the piece that is left.Then you cut off half of the remaining piec

7nadin3 [17]

It goes like this 1/2, 1/4, 1/8. But if your asking about what fraction didn’t get affected than that just zero because the original peace was cut in half.

If that’s not what you mean can you please elaborate to me!

7 0

3 years ago

he owner of a local supermarket wants to estimate the difference between the average number of gallons of milk sold per day on w

stellarik [79]

Answer:

90% confidence interval is ( -149.114, -62.666 )

Step-by-step explanation:

Given the data in the question;

Sample 1 Sample 2

x"₁ = 259.23 x"₂ = 365.12

s₁ = 34.713 s₂ = 48.297

n₁ = 5 n₂ = 10

With 90% confidence interval for μ₁ - μ₂ { using equal variance assumption }

significance level ∝ = 1 - 90% = 1 - 0.90 = 0.1

Since we are to assume that variance are equal and they are know, we will use pooled variance;

Degree of freedom DF = n₁ + n₂ - 2 = 5 + 10 - 2 = 13

Now, pooled estimate of variance will be;

$S_p^2$ = [ ( n₁ - 1 )s₁² + ( n₂ - 1)s₂² ] / [ ( n₁ - 1 ) + ( n₂ - 1 ) ]

we substitute

$S_p^2$ = [ ( 5 - 1 )(34.713)² + ( 10 - 1)(48.297)² ] / [ ( 5 - 1 ) + ( 10 - 1 ) ]

$S_p^2$ = [ ( 4 × 1204.9923) + ( 9 × 2332.6 ) ] / [ 4 + 9 ]

$S_p^2$ = [ 4819.9692 + 20993.4 ] / [ 13 ]

$S_p^2$ = 25813.3692 / 13

$S_p^2$ = 1985.64378

Now the Standard Error will be;

$S_{x1-x2$ = √[ ( $S_p^2$ / n₁ ) + ( $S_p^2$ / n₂ ) ]

we substitute

$S_{x1-x2$ = √[ ( 1985.64378 / 5 ) + ( 1985.64378 / 10 ) ]

$S_{x1-x2$ = √[ 397.128756 + 198.564378 ]

$S_{x1-x2$ = √595.693134

$S_{x1-x2$ = 24.4068

Critical Value = $t_{\frac{\alpha }{2}, df$ = $t_{0.05, df=13$ = 1.771 { t-table }

So,

Margin of Error E = $t_{\frac{\alpha }{2}, df$ × [ ( $S_p^2$ / n₁ ) + ( $S_p^2$ / n₂ ) ]

we substitute

Margin of Error E = 1.771 × 24.4068

Margin of Error E = 43.224

Point Estimate = x₁ - x₂ = 259.23 - 365.12 = -105.89

So, Limits of 90% CI will be; x₁ - x₂ ± E

Lower Limit = x₁ - x₂ - E = -105.89 - 43.224 = -149.114

Upper Limit = x₁ - x₂ - E = -105.89 + 43.224 = -62.666

Therefore, 90% confidence interval is ( -149.114, -62.666 )

3 0

3 years ago

Pherris is graphing the function f(x) = 2(3)x. He begins with the point (1, 6). Which could be the next point on his graph?

Maurinko [17]

the next point would be (2,18)

4 0

3 years ago

Read 2 more answers

Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final c

Black_prince [1.1K]

Answer:

The test statistic value Z = 4.64 > 1.96 at 0.05 level of significance

Null hypothesis is rejected

Alternative hypothesis is accepted

Test the claim that the proportion of all children in the town who suffer not from asthma is 11%

Step-by-step explanation:

Step(i):-

Given sample size 'n' = 167

Given data In a sample of 167 children selected randomly from one town, it is found that 37 of them suffer from asthma.

Sample proportion

$p^{-} = \frac{x}{n} = \frac{37}{167} = 0.2215$

Given Population proportion 'P' = 11% = 0.11

Step(ii) :-

Null Hypothesis : H₀ : p = 11

Alternative Hypothesis H₁: p≠11

Test statistic

$Z = \frac{p^{-} -P }{\sqrt{\frac{P Q}{n} } }$

$Z = \frac{0.2215 -0.11 }{\sqrt{\frac{0.11 X 0.89}{167} } }$

Z = 4.64

step(iii)

Critical value Z = 1.96

The calculated value Z = 4.64 > 1.96 at 0.05 level of significance

Null hypothesis is rejected

Alternative hypothesis is accepted

Conclusion:-

Test the claim that the proportion of all children in the town who suffer not from asthma is 11%

4 0

3 years ago

The answer to a subtraction problem​

The answer to a subtraction problem