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3 years ago

5

What is a dead ball?

1 answer:

Dimas [21]3 years ago

4 0

For volleyball a dead ball is, A ball not in play following a point, side-out or any other decision of the referee temporarily suspending play.

For basketball the ball is considered dead, such as when a foul has been committed and called by a referee, a foul shot has been attempted and another one is yet to be attempted, or the ball has gone out of bounds. Player substitutions may then be made.

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A person wearing a shoulder harness can survive a car crash if the acceleration is smaller than -300 m/s . assuming constant acc

mars1129 [50]

To solve this problem, we use the equation:

<span>d = (v^2 - v0^2) / 2a</span>

where,

d = distance of collapse

v0 = initial velocity = 101 km / h = 28.06 m / s

v = final velocity = 0

a = acceleration = - 300 m / s^2

d = (-28.06 m / s)^2 / (2 * - 300 m / s^2)

<span>d = 1.31 m</span>

3 0

3 years ago

What is the explanation for the fact that the desert sand is very hot in the day and very cool at night? 1. Sand reflects light

zepelin [54]

3. Sand has a low specific heat compared to air

5 0

3 years ago

A particle's position is given by z(t) = −(6.50 m/s2)t2k for t ≥ 0. (Express your answer in vector form.) a. Find the particle's

blondinia [14]

Answer:

a) $z'(t) =v(t) = -13t$

Now we can replace the velocity for t=1.75 s

$v(1.75s) = -13*1.75 =-22.75 \frac{m}{s}$

For t = 3.0 s we have:

$v(3.0s) = -13*3.0 =-39 \frac{m}{s}$

b) $v_{avg}= \frac{z_f - z_i}{t_f -t_i}$

And we can find the positions for the two times required like this:

$z_f = z(3.0s) = -(6.5 \frac{m}{s^2}) (3.0s)^2=-58.5m$

$z_i = z(1.75s) = -(6.5 \frac{m}{s^2}) (1.75s)^2=-19.906m$

And now we can replace and we got:

$V_{avg}= \frac{-58.5 -(-19.906) m}{3-1.75 s}= -30.875 \frac{m}{s}$

Explanation:

The particle position is given by:

$z(t) = -(6.5 \frac{m}{s^2}) t^2, t\geq 0$

Part a

In order to find the velocity we need to take the first derivate for the position function like this:

$z'(t) =v(t) = -13t$

Now we can replace the velocity for t=1.75 s

$v(1.75s) = -13*1.75 =-22.75 \frac{m}{s}$

For t = 3.0 s we have:

$v(3.0s) = -13*3.0 =-39 \frac{m}{s}$

Part b

For this case we can find the average velocity with the following formula:

$v_{avg}= \frac{z_f - z_i}{t_f -t_i}$

And we can find the positions for the two times required like this:

$z_f = z(3.0s) = -(6.5 \frac{m}{s^2}) (3.0s)^2=-58.5m$

$z_i = z(1.75s) = -(6.5 \frac{m}{s^2}) (1.75s)^2=-19.906m$

And now we can replace and we got:

$V_{avg}= \frac{-58.5 -(-19.906) m}{3-1.75 s}= -30.875 \frac{m}{s}$

8 0

3 years ago

A young girl is on a swing that completes 35.0 cycles in 25 seconds. What are her frequency and period?

fgiga [73]

The first question has the answer to your problem! I found the answer key!

3 0

3 years ago

For work to be accomplished we must have?

KiRa [710]

Answer:

a force and a movement in the same direction as the force.

Explanation:

4 0

4 years ago