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2 years ago

6

A discrete spectral line occurs at an angle of 9.1° in the first order spectrum. If the grating has 3,660 lines/cm, what is the

wavelength of this color of light?

1 answer:

KonstantinChe [14]2 years ago

8 0

Answer:

your answer would be c !

Explanation:

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A force of 166 N acts on a 7.05-kg bowling ball for .39 seconds . What is the bowling balls change in velocity

dimaraw [331]

Answer:

9.17 m/s

Explanation:

Impulse = change in momentum

FΔt = mΔv

(166 N) (0.39 s) = (7.06 kg) Δv

Δv = 9.17 m/s

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3 years ago

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2 cultural practices for cultivation of tomatoes

Brut [27]

Mulching and Staking

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2 years ago

Which statements below are true?

Ilya [14]

The correct statements are that the speed decreases as the distance decreases and speed increases as the distance increases for the same time.

Answer:

Option A and Option B.

Explanation:

Speed is defined as the ratio of distance covered to the time taken to cover that distance. So Speed = Distance/Time. In other words, we can also state that speed is directly proportional to the distance for a constant time. Thus, the speed will be decreasing as there is decrease in distance for the same time. As well as there will be increase in speed as the distance increases for the same time. So option A and option B are the true options. So if there is decrease in the distance due to direct proportionality the speed will also be decreasing. Similarly, if the distance increases, the speed will also be increasing.

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3 years ago

a 91.5 kg football player running east at 3.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft

Lesechka [4]

The final velocity is 3.47 m/s east

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the two players before and after the collision must be conserved:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$

where:

$m_1 = 91.5 kg$ is the mass of the first player

$u_1 = 3.73 m/s$ is the initial velocity of the first player (we take east as positive direction)

$m_2 = 63.5 kg$ is the mass of the second player

$u_2 = 3.09 m/s$ is the initial velocity of the second player

$v$ is their final combined velocity after the collision

Re-arranging the equation and substituting the values, we find:

$v = \frac{m_1 u_1+m_2 u_2}{m_1+m_2}=\frac{(91.5)(3.73)+(63.5)(3.09)}{91.5+63.5}=3.47 m/s$

So, their velocity afterwards is 3.47 m/s east.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

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3 years ago

The speed of an aircraft is measure in the unit_

slega [8]

Answer:

knot...

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2 years ago