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4 years ago

Compare and contrast sodium and fluorine? Compare and contrast oxygen and hydrogen?

1 answer:

6 0

sodium is found in group one element, but flourine members of halogens . oxygen found in group six element ,but hydrogen found in group 1( according to periodic table)

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Cyclist A is moving at 20.0 m/s whereas cyclist B is moving at 12.0 m/s in the same direction and is initially ahead ofA. When t

stealth61 [152]

Answer:

$v_{fA} = 28 \frac{m}{s}$

Explanation:

The kinematic parameters from the moment the two cyclists begin to accelerate until they meet are:

Initial parameters:

$v_{oA} = 20 m/s$ : Initial speed of cyclist A

$v_{oB} = 12 m/s$ : Initial speed of cyclist B

Final parameters:

$v_{fB} = 20 m/s$ : Final speed of cyclist B

$d_{A} = d_{B}$

distance of cyclist A = distance of cyclist B

$t_{A} =t_{B} = 12s$

time of cyclist A = time of cyclist B

Cyclist B Kinematics

$v_{fB} = v_{oB} +a_{B} *t\\$

$36= 12 + a_{B} *12$

$a_{B} = \frac{36-12}{12}$

$a_{B} = 2 \frac{m}{s^{2} }$

$d_{B} =( v_{oB})*( t)+( \frac{1}{2} )*(a_{B})* (t)^{2}$

$d_{B} =( 12*(12)+( \frac{1}{2} )*(2)* (144)}$

$d_{B} = 288m$

Cyclist A Kinematics

$d_{A} =( v_{oA})*( t)+( \frac{1}{2} )*(a_{A})* (t)^{2}$

$d_{A} =(20*( 12)+( \frac{1}{2} )*(a_{A})* 144}$

$d_{A} = 240 + 72*(a_{A})$

$288=240+72*(a_{A} )$

$a_{A} = \frac{288-240}{72}$

$a_{A} = 0.67 \frac{m}{s^{2} }$

$v_{fA} = v_{oA} + a_{A} * t$

$v_{fA} = 20 + 0.67*12$

$v_{fA} = 28 \frac{m}{s}$

7 0

3 years ago

HELP PLEASE!

riadik2000 [5.3K]

Real, inverted and at the same point of the object

5 0

4 years ago

Read 2 more answers

You are working as an expert witness for an attorney who is suing a shipping company. The company operates ships that carry crud

AnnZ [28]

Answer:

56.7 m³

Explanation:

The radius of the circular area covered by the spill is 4.25 km

You can find the area covered by the spill by applying the formula for area of a circular surface

A=π×r² where π=3.14 and r=4.25km

A= 3.14×4.25² = 56.72 km²

Remember the total area is on average at 1 micron (1μm) thick.This is to say

1μm=1m³

So the minimum volume of oil covering the ocean surface in meters will be;

Change km² to m²

56.72 km²= 56.72×1000000=5.67×10⁷ m²

Finding the volume;

Volume = Area * thickness

Volume= 5.67×10⁷ m² * 1× 10⁻⁶ = 56.7 m³

Minimum amount of oil that was spilled is 56.7 m³

3 0

3 years ago

Starting from rest, an intern pushes a 42-kggurney 12 m down the hall with a constant force of 80 N directed downward at an angl

DerKrebs [107]

Answer:

A. The work done by the intern is 792 J.

B. The velocity of the gurney when it has moved 12 m is 6.1 m/s.

C. The 12-m journey takes 3.8 s.

Explanation:

Hi there!

Please see the attached figure for a description of the situation.

Part A:

Work is done by a force when it is applied in the direction of the displacement or against it. In this case, the only force applied in the direction of displacement is the horizontal component of the force applied by the intern.

By trigonometry, the horizontal component of the force is calculated as follows:

cos θ = adjacent/hypotenuse

Looking at the figure, you can notice that the applied force, F, is the hypotenuse of a right triangle and the horizontal component, Fx, is the adjacent side:

cos θ = Fx / F

Fx = F · cos θ

Fx = 80 N · cos 35°

Fx = 66 N

Now we can calculate the work (W) done by this force:

W = Fx · x

Where x is the displacement:

W = 66 N · 12 m = 792 J

The work done by the intern is 792 J.

Part B:

Applying the work-energy theorem, the work done is equal to the change in kinetic energy:

W = final kinetic energy - initial kinetic energy

Since the gurney starts from rest, the initial kinetic energy is zero. Then:

W = final kinetic energy

The equation of kinetic energy (KE) is the following:

KE = 1/2 · m · v²

Where:

m = mass of the gurney.

v = velocity.

KE = 792 J

792 J = 1/2 · 42 kg · v²

v²= 2· 792 J / 42 kg

v = 6.1 m/s

The velocity of the gurney when it has moved 12 m is 6.1 m/s.

Part C:

First, let´s find the acceleration of the gurney:

Fx = m · a

Fx/m = a

66N / 42 kg = a

a = 1.6 m/s²

Now using the equation of velocity, let´s find the time at which the gurney has a velocity of 6.1 m/s:

v = v0 + a · t

Where:

v = velocity at time t.

v0 = initial velocity.

a = accleration.

t = time.

v = v0 + a · t

6.1 m/s = 0 + 1.6 m/s² · t

t = 6.1 m/s / 1.6 m/s²

t = 3.8 s

The 12-m journey takes 3.8 s.

3 0

3 years ago

Describe one piece of evidence to show light waves do not need a medium travel from one place to another

Art [367]

Answer:

I don't know I'm sorry I will tell you another answer asks me

5 0

3 years ago