Answer:
Gases, liquids and solids are all made up of microscopic particles.
Note that:
Particles in a:
gas are well separated with no regular arrangement.
liquid are close together with no regular arrangement.
solid are tightly packed, usually in a regular pattern.
Particles in a:
gas vibrate and move freely at high speeds.
liquid vibrate, move about, and slide past each other.
solid vibrate (jiggle) but generally do not move from place to place.
Liquids and solids are often referred to as condensed phases because the particles are very close together.
Explanation:
btw... IS THAT SPANISH?!
I HAD TO DO THIS ON ENGLISH LOLOLO
Answer:
F = 2.25 N
Explanation:
Given that,
Charge 1, 
Charge 2, 
Distance between charges, d = 10 cm = 0.1 m
We need to find the electric force between charges. The formula that is used to find the electric force is given by

Hence, the force between charges is 2.25 N.
Answer and Explanation:
As per the question:
When the stone is thrown from the cliff top and hits the ground below eventually:
R = 
where
= initial velocity
H = height
g = acceleration due to gravity
R = horizontal Range
Now,
(a) Displacement of the stone is given by the horizontal range:
R = 
where
= initial velocity
H = height
g = acceleration due to gravity
R = horizontal Range
(b) Speed just prior to the impact is given by the third equation of motion:

where
v = final velocity
(c) Time of flight is given by the second eqn of motion where the initial velocity is considered to be 0 then:


T = 
Answer:
The magnitude of the magnetic flux through the loop is 0.0982 T.m²
Explanation:
Given;
magnitude of magnetic field, B = 0.5 T
radius of the loop, r = 0.25 m
Area of the loop is given by;
A = πr²
A = 3.142 x (0.25)²
A = 0.1964 m²
The magnitude of the magnetic flux through the loop is given by;
Ф = BA
Where;
B is the magnitude of the magnetic field
A is area of the field
Ф = 0.5 x 0.1964
Ф = 0.0982 T.m²
Therefore, the magnitude of the magnetic flux through the loop is 0.0982 T.m²
Answer:
Independent variable: Force applied to the car
Dependent variable: The acceleration of the car
Explanation:
A scientific experiment involves three variables which are classified mainly as independent, dependent and constant variables.
The independent variable is the variable which can be changed or changes itself like weather, natural conditions and in a given question, the applied force on the car is considered.
The dependent variable is the variable which depends on the independent variable that is the force applied on the car. Therefore, the acceleration of the car can be considered as a dependent variable as it changes according to the applied force.