Answer:
The gram is the basic unit of measurement
Explanation:
You use it to weigh small items such as sugar, flour, coffee, and other items that are similar.
If you want to measure in grams using a scale is the most accurate solution.
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On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 92.8 cm and diameter 2.05 cm from a storage room to a machinist, the weight of rod w is 23.41 N .
<h3>How is the weight calculated?</h3>
Given ,
density (d) = 7800 kg/m³
D = 2.05 cm = 0.0205 m
r = D/2 = 0.0205 / 2 =0.01025 m
h = 92.8 cm = 0.928 m
The weight is calculated by ,
W = m × g
But, to find mass (m)
m = d × V
The volume of the rod, because is cylindrical, is,
V = π × r² × h
∴ V = 3.14 × (0.01025)² × 0.928
∴ V = 3.14 × 1.051 × 10⁻⁴ × 0.928
∴ V = 3.0625 × 10⁻⁴
Now to calculate mass,
m = d × V
∴ m = 7800 × 3.0625 × 10⁻⁴
∴ m = 2.3887 Kg
Now, for calculating weight
W = m × g
∴ W = 2.3887 × 9.8
∴ W = 23.41 N
∴ The weight of the rod W assuming the free-fall acceleration is 23.41 N .
<h3>What is weight?</h3>
- The weight of an object is the force exerted on it by gravity.
- It is define weight as a vector quantity, the force of gravity acting on an object.
- Some define weight as a scalar quantity that is the magnitude of gravity.
Can learn more about weight calculation from brainly.com/question/15685221
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The acceleration would be 2.5 m/sec^2
A= acceleration
F= force
M= mass
A = f/m
125N/50kg=2.5 m/s^2
Answer:
a. 1/1000 sec
Explanation:
Shutter speed is the length of time that the film you’re photographing is being exposed to the scene in film photography. However, in digital photography, shutter speed is the length of time that the image sensor sees the scene the photographer is trying to capture.
For shutter speeds, the greater the denominator the higher the speed and the lower the denominator, the lower the speed.
Thus, the fastest one is option A.
velocity = traveled distance ÷ time of the traveled distance is seconds
velocity = 600 ÷ 60
velocity = 10 m/s
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Kinetic Energy = 1/2 × mass × ( velocity )^2
KE = 1/2 × 60 × ( 10 )^2
KE = 30 × 100
KE = 3000 j