Small fragments of orbiting bodies that have fallen on Earth's surface are known as

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wolverine [178]

The layers that make up the upper mantle are the following.

The lithosphere and the asthenosphere.
The lithosphere and the asthenosphere are the layers that make up the upper mantle.
The rocky outer part of the Earth is called the lithosphere.
It is very rigid, solid, and it is not as hot as the other parts.
According to scientists, its thickness is about 90 to 100 kilometers from the surface of the earth.
The layer of the Earth that moves the lithospheric plates is called the asthenosphere.
Lithospheric plates are 60 miles long on average and are composed of continental crust.

We conclude that the lithosphere and the asthenosphere are the layers that make up the upper mantle. The new lithosphere is being created at oceanic ridges due to plate tectonics. Yes, planet Earth is getting larger constantly.

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8 0

3 years ago

A wheel of radius R = 0.80 m is pulled by a rope looped around a frictionless axle. The total mass of the wheel and axle assembl

iragen [17]

Answer:

$\frac{K_T}{K_R}=\frac{600J}{188.63J}=3.18$

Explanation:

To find the rotational kinetic energy you first calculate the angular acceleration by using the following formula:

$\tau=I\alpha\\\\FR=I\alpha\\\\\alpha=\frac{FR}{I}$

F: force applied

R: radius of the wheel

I: moment of inertia

$\alpha=\frac{(120N)(0.80m)}{26.88kgm^2}=3.57\frac{rad}{s^2}$

With this value you calculate the angular velocity:

$\omega^2=\omega_o^2+2\alpha \theta\\$

you calculate how many radians the wheel run in 5.0m

$\theta=\frac{2\pi (0.8m)}{5.0m}=\approx1.00rad$

$\omega=\sqrt{2(3.57\frac{rad}{s^2})(1.00rad)}=2.67\frac{rad}{s}$

Next, you use the formula for the rotational kinetic energy:

$K_R=\frac{1}{2}I\omega^2=(26.88)(2.67)^2 J = 188.63J$

For the transnational kinetic energy you use the following equation:

$W=\Delta K_T$ (net work equals the change in the kinetic energy).

By replacing the you obtain:

$\Delta K_T=Fd=(120)(5.0)J=600J$

Finally, the ratio between translational rotational kinetic energy is:

$\frac{K_T}{K_R}=\frac{600J}{188.63J}=3.18$

hence, translational kinetic energy is three times the rotational kinetic energy.

6 0

3 years ago

Un cuerpo recibe una fuerza de 100N y produce una aceleracion de 2 m/s² determine la masa del cuerpo

kykrilka [37]

Answer:

The mass of the body is 50 kg.

Explanation:

We have,

Force acting on a body is 100 N

Acceleration of the body is 2 m/s²

It is required to find the mass of the body. The force acting on a body is given by :

F = ma

$m=\dfrac{F}{a}\\\\m=\dfrac{100}{2}\\\\m=50\ kg$

So, the mass of the body is 50 kg.

3 0

3 years ago

you weight 650 N. What would you wieght if the Earth were four times as massive as it is and its raduis were three times its pre

LiRa [457]

To solve this problem we will apply the concept given by the law of gravitational attraction, which properly defines gravity under the function

$g = \frac{GM}{r^2}$

Here,

G = Gravitational Universal Constant

M = Mass of Earth

r = Distance between the human and the center of mass of the Earth

The acceleration due to gravity when is 4 times the mass of Earth and 3 times the radius would be given as,

$g_1 = \frac{GM}{r^2}$

$g_2 = \frac{G(4M)}{(3r)^2}$

$g_2 = \frac{4GM}{9r^2}$

$g_2 = \frac{4}{9} g_1$

The weight is defined as

$W = mg_1$

So the new weight would be given as

$W' = mg_2$

$W' = m(\frac{4}{9} g_1 )$

$W' = \frac{4}{9} mg_1$

$W' = \frac{4}{9} W$

$W' = \frac{4}{9}(650)$

$W' = 288.8N$

Therefore the weight under this condition is 288.8N

5 0

3 years ago

1 point

OlgaM077 [116]

Answer:

true

Explanation:

momentum = kg (m/s)

momentum = mass × velocity

5 0

3 years ago