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3 years ago

The measurement 0.41006 gram, rounded to three significant figures, is expressed as

Chemistry

1 answer:

atroni [7]3 years ago

3 0

Answer:

option B = 0.410 g

Explanation:

The given measurement have five significant figures 41006. this measurement can be rounded to three significant figures i.e, 0.410 g.

All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.

Leading zeros are not consider as a significant figures. e.g. 0.03 in this number only one significant figure present which is 3.

Zero between the non zero digits are consider significant like 104 consist of three significant figures.

The zeros at the right side e.g 2400 are also significant. There are four significant figures are present.

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The temperature of a 100.0 g sample of water is raised from 30degrees celsius to 100.0 degrees celsius. How much energy is requi

worty [1.4K]

Answer:

29260J

Explanation:

Given parameters:

Mass of water sample = 100g

Initial temperature = 30°C

Final temperature = 100°C

Unknown:

Energy required for the temperature change = ?

Solution:

The amount of heat required for this temperature change can be derived from the expression below;

H = m c (ΔT)

H is the amount of heat energy

m is the mass

c is the specific heat capacity of water = 4.18J/g°C

ΔT is the change in temperature

Now insert the parameters and solve;

H = 100 x 4.18 x (100 - 30)

H = 100 x 4.18 x 70 = 29260J

6 0

2 years ago

Which of the following shows the conservation of mass during cellular respiration? 3 CO2 3 H2O energy → 3 C6H12O6 3 O2 6 CO2 6 H

Thepotemich [5.8K]

The reaction that has been, following the law of conservation of mass has been $\rm C_6H_1_2O_6\;+\;6\;O_2\;\rightarrow\;6\;CO_2\;+\;6\;H_2O\;+\;Energy$ .

The law of conservation has been given in the chemical reaction that there has been no loss or gain of the mass and energy.

The law of conservation has been evident when there has been an equal number of atoms of each element on the product and the reactant side.

<h3 /><h3>Conservation of mass in Cellular respiration</h3>

The following reactions have been identified as:

$\rm 3\;CO_2\;+\;3\;H_2O\;+\;Energy\;\rightarrow\;3\;C_6H_1_2O_6$

Carbon atoms

Reactant = 3

Product = 18

Oxygen atoms

Reactant = 9

Product = 18

Hydrogen atoms

Reactant = 6

Product = 36

The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.

$\rm 3\;O_2\;+\;6\;CO_2\;+\;6\;H_2O\;+\;Energy\;\rightarrow\;C_6H_1_2O_6\;+\;6\;O_2$

Carbon atoms

Reactant = 6

Product = 6

Oxygen atoms

Reactant = 24

Product = 18

Hydrogen atoms

Reactant = 12

Product = 12

The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.

$\rm C_6H_1_2O_6\;+\;6\;O_2\;\rightarrow\;6\;CO_2\;+\;6\;H_2O\;+\;Energy$

Carbon atoms

Reactant = 6

Product = 6

Oxygen atoms

Reactant = 18

Product = 18

Hydrogen atoms

Reactant = 12

Product = 12

The number of atoms is equal on the product and reactant side, thus follows the law of conservation of mass.

$\rm 6\;H_2O\;+\;C_6H_1_2O_6\;\rightarrow\;6\;O_2\;+\;Energy$

Carbon atoms

Reactant = 6

Product = 0

Oxygen atoms

Reactant = 12

Product = 12

Hydrogen atoms

Reactant = 24

Product = 0

The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.

Thus, the reaction that has been following the law of conservation of mass has been $\rm C_6H_1_2O_6\;+\;6\;O_2\;\rightarrow\;6\;CO_2\;+\;6\;H_2O\;+\;Energy$ .

Learn more about law of conservation, here:

brainly.com/question/2175724

4 0

1 year ago

Determine the mass of a ball with a wavelength of 3.45 × 10-34 m and a velocity of 6.55 m/s

Yuki888 [10]

<span>293 grams The formula for the wavelength of a massive particle is Î» = h/p where Î» = wavelength h = Plank constant (6.626070040Ă—10^â’34 J*s) p = momentum (mass times velocity) So let's solve for momentum and from there get the mass Î» = h/p Î»p = h p = h/Î» Substitute known values and solve p = 6.626070040Ă—10^â’34 J*s/3.45Ă—10^-34 m p = 1.92 J*s/m Since momentum is the product of mass and velocity, we have p = M * V p/V = M So substitute again, and solve. p/V = M 1.92 J*s/m / 6.55 m/s = M 1.92 kg*m/s / 6.55 m/s = M 1.92 kg*m/s / 6.55 m/s = M 0.293 kg = M So the mass is 293 grams</span>

6 0

3 years ago

Read 2 more answers

How does maximum boiling azeotropic mixture is separated using fractional distillation?

Evgesh-ka [11]

Answer:

By heating the mixture to maximum boiling point and then the solution is distilled at a constant temperature without having a change in composition.

Explanation:

An azeotropic mixture is also called a constant boiling mixture and it is a mixture of two or more liquids whose proportions cannot be altered by simple distillation due to the fact that when an azeotropic mixture is boiled, the vapor has the same proportions of constituents as the unboiled mixture.

Now, maximum boiling azeotropic mixture are the solutions with negative deviations that have an intermediate composition for which the vapor pressure of the solution is minimum and as a result, the boiling point is maximum. At that point, the solution will distill at a constant temperature without having a change in composition.

4 0

1 year ago

V2 = (P1 × V1 × T2) (P2 × T1) A gas with a beginning pressure of 2 atm at a temperature of 300 K has a volume of 20 ml. What wil

rusak2 [61]

6.6ml will be the new volume if the pressure increases to 4 atm and the temperature are lowered to 200 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

$V_1=20 ml$