Answer:
- Alcohol
- Ether
- Arene
- Amine
Explanation:
In the attached picture you may find the structure of betaxolol.
You can see the alcohol group C-O-H as well as the ether group C-O-C.
The arene -or aromatic ring- can also be seen.
There's also a secondary amine group, C-NH-C.
Answer:
4.7485 g
Explanation:
4.50 x 10^22 Cu atoms * (1 mol Cu / 6.022 x 10^23 Cu atoms) * 63.546 g Cu/(mol Cu) = 4.7485 g
In every mole of Cu, there are 6.022 x 10^23 atoms (Avogadro's number). The molecular weight of copper is 63.546 g/mol.
Answer:
Nonmetal oxides react with water to form oxyacids. Ex. CO2 + H2O → H2CO3 Page 3 Decomposition - compound (reactant) breaks down into 2 or more simpler substances.
Crystallization above the ground and crystallization below the ground
The common neutralization reaction that involve NaOH reacting with HNO3 produces
NaNO3 and H2O
The equation for reaction is as folows
NaOH + HNO3 = NaNO3 + H2O
that is 1 mole of NaOH reacted with 1 mole of HNO3 to form 1 mole of NaNO3 and 1 mole of H2O