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Assoli18 [71]
4 years ago
5

In a colloid, solution, or suspension, particles are dispersed throughout the mixture. What is the order of these three types of

mixtures, from the smallest particle size to the largest?
Chemistry
2 answers:
a_sh-v [17]4 years ago
4 0
1) solution
2) colloid
3) suspension
Triss [41]4 years ago
3 0

<u>Answer: </u>Order of mixtures having particle size smallest to large is:

\text{Solution }

<u>Explanation:</u>

The solutions are classified into 3 types on the basis of size of the particles.

1.) Solution: When the particle size is between 0.1 nm to 1 nm, then the solution is considered as a true solution.

2,) Colloid: When the particle size is between 2 to 1000 nm, then the solution is considered as a colloid.

3.) Suspension: When the particle size is greater than 1000 nm, then the solution is considered as a suspension.

Hence, the order of mixtures having particle size smallest to large is:

\text{Solution }

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A student performed a chemical reaction in which 35 grams of hydrogen and 65 grams of oxygen reacted to form water. What is the
sergejj [24]

Answer:

The mass of the product is 73,06 g

Explanation:

The reaction to form water is:

2H2 + O2 ---> 2H2O

35 g     65 g

Molar mass H2 = 2g/m ---> I have 17,5 moles (35g / 2 g/m)

Molar mass O2 = 32g/m ---> I have 2,03 moles (65g / 32g/m)

2 moles of H2 __reacts with __ 1 mol O2

17,5 moles of H2 __ reacts with ___ (17,5 m . 1 m) / 2 m = 8,75 m

I have just 2,03 m of O2 and I need 8,75 m so O2 is my limiting reagent

1 mol of O2 ___ reacts with 2 moles H2

2,03 moles of O2 __ reacts with  (2,03 m . 2 m) / 1 m = 4,06 m

I have 17,5 moles of H2 and I need 4,06 m. H2 is my excess reagent

<u><em>"All operations are done with the limiting reagent"</em></u>

1 mol O2 are required____ to form 2 H2O

2,03 mol O2 are required __ to form (2,03m . 2m) / 1m = 4,06 m

Molar mass of water: 18 g/m

Mass of water ----> Molar mass . Moles water = 18 g/m . 4,06 m = 73,08g

8 0
3 years ago
If 5000 balloons are each filled with 0.5L then how many does each balloon have
Colt1911 [192]
ANSWER:

If 5000 balloons are each filled with 0.5L, then each balloon has 0.5L. The answer is in the question.

Please mark as brainliest if you found this helpful! :)
Thank you <3
5 0
4 years ago
As the tempreture of a liquid increases the solubility of a liquid of that liquid
anzhelika [568]
As the temperature increases, the solubility of the solute in the liquid also increases.  This is due to the fact that the increase in energy allows the liquid to more effectively break up the solute.  The additoin of energy also shifts the equilibrium of the reation to the right since it takes energy to dissolve most things and you are adding more of it (this is explained with Le Chatlier principles).

I hope this helps and also I assumed that your question involved the solubility of an ionic substance in a solvent like water.  If that was not your question feel free to say so in the comments so that I can answer your actually question.
8 0
3 years ago
What is the pH of a 0.300 M NH₃ solution that has Kb = 1.8 × 10⁻⁵ ? The equation for the dissociation of NH₃ is: NH₃ (aq) + H₂O
nalin [4]

Answer:

11.4

Explanation:

Step 1: Given data

  • Concentration of the base (Cb): 0.300 M
  • Basic dissociation constant (Kb): 1.8 × 10⁻⁵

Step 2: Write the dissociation equation

NH₃(aq) + H₂O(l) ⇄ NH₄⁺(aq) + OH⁻(aq)

Step 3: Calculate the concentration of OH⁻

We will use the following expression.

[OH^{-} ]=\sqrt{Kb \times Cb } = \sqrt{1.8  \times 10^{-5} \times 0.300 } = 2.3 \times 10^{-3} M

Step 4: Calculate the pOH

We will use the following expression.

pOH =-log[OH^{-} ]= -log(2.3 \times 10^{-3} M) = 2.6

Step 5: Calculate the pH

We will use the following expression.

pH+pOH=14\\pH = 14-pOH = 14-2.6 = 11.4

8 0
3 years ago
When equal moles of an acid and a base are mixed, after reaction the two are compounds are said to be at the _______________. Se
Elodia [21]

Answer:

when equal moles of an acid and base are mixed,after reaction the two are compounds are said to be at the Equivalent point.

3 0
3 years ago
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