Titration is a technique for determining unknown molarity of acid by adding a base of know malarkey to a known volume of acid
The process of calculating the quantity of a material A by adding measured increments of substance B, the titrant, with which it reacts until exact chemical equivalency is obtained (the equivalence point)" is the definition of titration. Titration, commonly referred to as titrimetry, is a method of chemical qualitative analysis used to determine the concentration of a certain analyte in a mixture. The goal of titration is to identify the equivalence point, or the point at which chemically equivalent amounts of the reactants have been combined, which is a key analytical chemistry technique also known as volumetric analysis. The stoichiometry of the reactants determines how many reactants have been mixed at the equivalence point.
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Answer:
Here's what I get
Explanation:
I think this may be the equation you intended to write:
C₃H₅(OH)₃ + 3HCl ⟶ C₃H₅Cl₃ + 3H₂O
The mole ratios are the ratios of the coefficients in the balanced equation.
Here are some of the possible molar ratios.
- C₃H₅(OH)₃:HCl = 1:3
- C₃H₅(OH)₃:C₃H₅Cl₃ = 1:1
- C₃H₅(OH)₃:H₂O = 1:3
- HCl:C₃H₅Cl₃ = 3:1
- HCl:H₂O = 3:3
- C₃H₅Cl₃:H₂O = 1:3
Answer:
No. of protons = 34
Explanation:
First we need to calculate the number of electrons in one mole of the the element:
No. of electrons per mole = Total Mass of Electrons/Mass of 1 Electron
No. of electrons per mole = (18.65 x 10⁻³ g)/(9.109 x 10⁻²⁸ g)
No. of electrons per mole = 2.04 x 10²⁵ electrons/mol
Now, we calculate the no. of electrons in 1 atom:
No. of electrons per atom = No. of Electrons per mole/No. of atoms per mole
No. of electrons per atom = (2.04 x 10²⁵ electrons/mol)/(6.022 x 10²³ atoms/mol)
No. of electrons per atom = 34 electrons/atom
Since, the no. of protons in a pure element are equal to the number of electrons. Therefore,
<u>No. of protons = 34</u>
Answer:
17.25 L
Explanation:
I converted 100g into moles and converted the amount of moles into L.
Answer:
i) Neon (Ne)
ii) Fluoride Ion (F⁻¹)
iii) Oxide Ion (O⁻²)
Explanation:
Ions are those charged species which are either positively charged (by loosing electrons) called as cations or negatively charged (by gaining electrons) called as anions.
In given examples, Neon is a neutral atom which has an atomic number 10. It contains 10 electrons in its neutral state with the electronic configuration 1s², 2s², 2p⁶.
Fluorine atom has an atomic number of 9. Therefore, it contains 9 electrons in its neutral state with an electronic configuration of 1s², 2s², 2p⁵. When Fluorine atom gains one electron it gets 10 electrons with electronic configuration of 1s², 2s², 2p⁶.
Oxygen atom has an atomic number of 8. Therefore, it contains 8 electrons in its neutral state with an electronic configuration of 1s², 2s², 2p⁴. When Oxygen atom gains two electron it gets 10 electrons with electronic configuration of 1s², 2s², 2p⁶ forming an Oxide Ion.