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RSB [31]
3 years ago
8

A saline solution with a mass of 400 g has 30 g of NaCl dissolved in it. What is the mass/mass percent concentration of the solu

tion?
Chemistry
1 answer:
maria [59]3 years ago
3 0
(g solute/g solution)*100 = % mass/mass

30 g / 400 * 100 

0,075 * 100

= 7,5% w/w

hope this helps!

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Which molecule will undergo only london dispersion forces when interacting with other molecules of the same kind?.
Neko [114]

Molecules undergo London dispersion forces:

C_{4}H_{10} is the molecule will undergo only London dispersion forces when interacting with other molecules of the same kind.

What are London dispersion forces?

  • A sort of force that interacts between atoms and molecules that is often electrically symmetric is referred to as a London dispersion force.
  • When viewed from the nucleus, their electron distribution is frequently symmetrical. This dispersion force, which is also known as a transient attractive force, is frequently observed when the locations of the electrons in two nearby atoms cause the atoms to temporarily form dipoles.
  • The bond is polar when there are significant variations between the elements' electronegativities; it is nonpolar when there are similarities. When the molecule's dipole moment is equal to O, it is nonpolar; when it differs from O, it is polar.
  • The force at these molecules is known as the London dispersion force. In nonpolar molecules, the forces are weak, and partial charges must be induced so that they can bond. In polar molecules, partial charges caused by polarity result in a stronger link known as a dipole-dipole. The dipole-dipole is significantly stronger and known as a hydrogen bond if it is connected to a large electronegative atom (F, O, or N). Ionic force is the name for the attraction force at ionic substances.
  • The intermolecular force in the letter an is the London dispersion force because the compound is nonpolar;

<u>Reason for incorrect options:</u>

b: the compound is ionic because Na is a metal and the other part is covalent,

c: two compounds are possible: one is nonpolar and exhibits London dispersion force; the other is polar and exhibits dipole-dipole force; and

d: both compounds exhibit hydrogen bonds (H bonded to O, and H bonded to F).

NOTE: Your question is incomplete, but most probably your full question was, which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind? Which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind?

A. C_{4}H_{10}

B. NaC_{2}H_{3}O_{2}

C. CH_{2}C_{12}

D. C_{2}H_{5}OH HF

Learn more about the London dispersion forces here,

brainly.com/question/22388709

#SPJ4

4 0
2 years ago
Calculate the total volume of gas (at 119 ?c and 731 mmhg produced by the complete decomposition of 1.71 kg of ammonium nitrate.
Shtirlitz [24]
The reaction is:

NH4 (NO3) (s) ⇄ N2O (g) + 2 H2O (g)

This means that 1 mol of NH4 (NO3)s produces 3 moles of gases.

Now find the number of moles in 1.71 kg of NH4 (NO3)

Molar mass = 2*14g/mol + 4 * 1g/mol + 3*16g/mol = 80 g/mol

# moles = mass / molar mass = 1710 g / 80 g/mol = 21.375 mol of NH4(NO3)

We already said that every mol of NH4(NO3) produces 3 moles of gases, then the number of moles of gases produced is 3 * 21.375 = 64.125 mol

Now use the equation for ideal gases to fin the volume

pV = nRT => V = nRT / p = (64.125 mol)(0.082atm*liter / K*mol) * (119 +273)K / (731mmHg *1 atm/760mmHg) =

V = 2143.01 liters
4 0
3 years ago
A chemist prepares a solution of aluminum sulfite by measuring out 109 umol of aluminum sulfite into a 350 mL volumetric flask a
Tom [10]

Answer:

0.311 mmol/L

Explanation:

109  μmol = 109*10^(-6) mol

109*10^(-6) mol = 109*10^(-6) mol*(10^3 mmol/1mol) = 109*10^(-3) mmol =

=0.109 mmol

350 mL = 0.350 L

0.109 mmol/0.350 L = 0.311 mmol/L

8 0
4 years ago
• How many neutrons does the isotope gold-148 have.
Butoxors [25]
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4 0
3 years ago
Calculate the atomic mass of titanium. The five titanium isotopes have atomic masses and relative abundances of 45.953 amu (8.00
aniked [119]

The atomic mass of titanium is 47.88 u.

The average atomic mass of Ti is the <em>weighted average</em> of the atomic masses of its isotopes.

We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its % abundance).

Thus,  

0.0800 × 45.953 u =  3.676 u

0.0730 × 46.952 u =  3.427 u

0.7380 × 47.948 u = 35.386 u

0.0550 × 48.948 u =  2.692 u

0.0540 × 49.945 u =<u>  2.697 u </u>

_________TOTAL = 47.88 u


4 0
3 years ago
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