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3 years ago

12

Please help..... , click on it to get a better view :)

1 answer:

Vlad1618 [11]3 years ago

6 0

Answer:

Step-by-step explanation:

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The area of a square is always greater than its perimeter. Which of the following side-lengths for a square provides a counterex

marusya05 [52]

Answer:

a. 2

Step-by-step explanation:

Area of a square is calculated as:

$Area = Length * Length$

And the perimeter is

$Perimeter = 4 * Length$

For (a):

$Length = 2$

$Area = 2 * 2 = 4$

$Perimeter = 4 * 2 = 8$

For(b):

$Length = 4$

$Area = 4 * 4 = 16$

$Perimeter = 4 * 4 = 16$

For (c):

$Length=7.5$

$Area = 7.5 * 7.5-56.25$

$Perimeter = 4 * 7.5 = 30,$

For (d):

$Length = 10$

$Area = 10 * 10 = 100$

$Perimeter = 4 * 10 = 40$

For (e):

$Length = 125$

$Area = 125 * 125 =15625$

$Perimeter = 4 * 125 = 500$

From (a) to (e), only side length 2 has a higher perimeter.

Hence, it disproves the statement

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