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zavuch27 [327]

If you convert the number on a percent,
then multiply the number by 100 with sign %

1.04 = 1.04 × 100% = <u>104%</u>

4 0

3 years ago

Read 2 more answers

Can someone please help me with this ASAP‼️ Thank You

AVprozaik [17]

Let x = cost of the dishwasher.

The amounts the children are paying are:

Mark =20% = 1/5, so 1/5x

Sorin = 75

Raymond = 1/4x

Stephanie = 75

Kristin = 1/3x

Add them together:

x = 1/5x + 1/4x + 1/3x + 75 + 75

x - ( 1/5x + 1/4x + 1/3x ) = 150

Rewrite fractions with common denominator:

x - ( 12/60x + 15/60x + 20/60x ) = 150

60/60x - 47/60x = 150

13/60x = 150

x = 150/1 • 60/13

x = 9000/13

x = 692.31

The total cost of the dishwasher is $692.31

Now calculate the amount each child pays:

Mark = 1/5 x = 692.31/ 5 = $138.46

Sorin = $75.00

Raymond = 1/4 x = 692.31 / 4 = $173.08

Stephanie = $75.00

Kristin = 1/3 x = 692.31 / 3 = $230.77

5 0

4 years ago

In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

Marina86 [1]

Answer:

(a) 0.94

(b) 0.20

(c) 90.53%

Step-by-step explanation:

From a population (Bernoulli population), 90% of the bearings meet a thickness specification, let $p_1$ be the probability that a bearing meets the specification.

So, $p_1=0.9$

Sample size, $n_1=500$ , is large.

Let X represent the number of acceptable bearing.

Convert this to a normal distribution,

Mean: $\mu_1=n_1p_1=500\times0.9=450$

Variance: $\sigma_1^2=n_1p_1(1-p_1)=500\times0.9\times0.1=45$

$\Rightarrow \sigma_1 =\sqrt{45}=6.71$

(a) A shipment is acceptable if at least 440 of the 500 bearings meet the specification.

So, $X\geq 440.$

Here, 440 is included, so, by using the continuity correction, take x=439.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{339.5-450}{6.71}=-1.56$ .

So, the probability that a given shipment is acceptable is

$P(z\geq-1.56)=\int_{-1.56}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}}=0.94062$

Hence, the probability that a given shipment is acceptable is 0.94.

(b) We have the probability of acceptability of one shipment 0.94, which is same for each shipment, so here the number of shipments is a Binomial population.

Denote the probability od acceptance of a shipment by $p_2$ .

$p_2=0.94$

The total number of shipment, i.e sample size, $n_2= 300$

Here, the sample size is sufficiently large to approximate it as a normal distribution, for which mean, $\mu_2$ , and variance, $\sigma_2^2$ .

Mean: $\mu_2=n_2p_2=300\times0.94=282$

Variance: $\sigma_2^2=n_2p_2(1-p_2)=300\times0.94(1-0.94)=16.92$

$\Rightarrow \sigma_2=\sqrt(16.92}=4.11$ .

In this case, X>285, so, by using the continuity correction, take x=285.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{285.5-282}{4.11}=0.85$ .

So, the probability that a given shipment is acceptable is

$P(z\geq0.85)=\int_{0.85}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}=0.1977$

Hence, the probability that a given shipment is acceptable is 0.20.

(c) For the acceptance of 99% shipment of in the total shipment of 300 (sample size).

The area right to the z-score=0.99

and the area left to the z-score is 1-0.99=0.001.

For this value, the value of z-score is -3.09 (from the z-score table)

Let, $\alpha$ be the required probability of acceptance of one shipment.

So,

$-3.09=\frac{285.5-300\alpha}{\sqrt{300 \alpha(1-\alpha)}}$

On solving

$\alpha= 0.977896$

Again, the probability of acceptance of one shipment, $\alpha$ , depends on the probability of meeting the thickness specification of one bearing.

For this case,

The area right to the z-score=0.97790

and the area left to the z-score is 1-0.97790=0.0221.

The value of z-score is -2.01 (from the z-score table)

Let $p$ be the probability that one bearing meets the specification. So

$-2.01=\frac{439.5-500 p}{\sqrt{500 p(1-p)}}$

On solving

$p=0.9053$

Hence, 90.53% of the bearings meet a thickness specification so that 99% of the shipments are acceptable.

8 0

4 years ago

∠F and ∠G are supplementary angles. If m∠F is two less than six times the measure of ∠G, find the measures of both angles

Mnenie [13.5K]

Answer:

∠ G = 26°, ∠ F = 154°

Step-by-step explanation:

Express ∠ F in terms of ∠ G, that is

F = 6G - 2

and since the angles are supplementary, then

G + 6G - 2 = 180, that is

7G - 2 = 180 ( add 2 to both sides )

7G = 182 ( divide both sides by 7 )

G = 26

Thus

∠ G = 26° and ∠ F = 6(26) - 2 = 156 - 2 = 154°

4 0

3 years ago

A leprechaun places a magic penny under a girl's pillow. The next night there are 2 magic pennies under her pillow. Each night

11Alexandr11 [23.1K]

Answer:

tn = 2097152 pennies
tn = 20971.52 dollars.

Step-by-step explanation:

A surprisingly large amount of money.

The question is "Does the amount of money just double or do the previous amounts add to the present amount?"

I think it just doubles. Not only that, but she can't spend any of it until night 22 is reached.

tn = a*2^(n - 1)
a = 1 She starts with 1 penny.
n = 22
tn = 1*2^(22 - 1)
tn = 1*2^21
tn = 2097152 pennies
tn = 20971.52 dollars.

8 0

4 years ago