First find the time that the ball is level with the top of the building on its descent. You can do this by solving 280 = -16^2 + 48t + 280 for t. This gives t = 3 seconds .
Then when the ball reaches the ground the time t is obtained by solving 0 = -16t^2 + 48t + 280 This gives t = 5.94 seconds.
Answer in interval notation is (3, 5.94].
Answer:
Not congruent.
Step-by-step explanation:
They are not congruent because the first one has ASA and the second one is AAS.
Answer:
Answer: A. x + (4x - 85) = 90
In this case, the two angles are complementary. This means they add up to 90°. Therefore, the equation is x + (4x - 85) = 90.
Step-by-step explanation:
R(7)=????
r(n)=0.009n s0 n=7
r(7)=0.009(7)
r(7)=0.063
Ideal timeline of the dance routine = 4 minutes = 4 × 60 seconds = 240 seconds
Variation allowed in the dance routine timeline = +- 5 seconds
Let the timeline of the dance routine be T
⇒ 240 seconds - 5 seconds < T < 240 seconds + 5 seconds
⇒ 235 seconds < T < 245 seconds
⇒ 
minutes < T < 
minutes
⇒ 3.92 minutes < T < 4.08 minutes
So the least possible time of the dance routine can be 3.92 minutes (or 235 seconds) and the greatest possible time of the dance routine can be 4.08 minutes (or 245 seconds)
