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3 years ago

Slope intercept form write an equation

Mathematics

2 answers:

Mama L [17]3 years ago

4 0

Use y=mx+b to form your equation with the information already provided

wariber [46]3 years ago

3 0

The Equation for slope intercept form is y= mx + b

Y= Dependent variable
M= Slope
X= Unknown variable
B+ Y intercept

Examples:
1. Y= 3x=4

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Length,breadth & diagonal of a cuboid are 60 cm,20 cm & 65 cm respectively. find its volume?

Lera25 [3.4K]

I hope this helps you

Volume=60.20.65

Volume=78000

7 0

3 years ago

Solve:- 7^5 Thanks!!!!!!!!!!!!!

solong [7]

These are exponents. To solve an exponent you need to multiply the base it self how many times its says in the power.

a²

a = base
2 = power

7^5 = 7 × 7 × 7 × 7 × 7 = 16807
7^5 = 16807

3 0

3 years ago

Read 2 more answers

Calculus Problem

Roman55 [17]

The two parabolas intersect for

$8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2$

and so the base of each solid is the set

$B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}$

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, $|x^2-(8-x^2)| = 2|x^2-4|$ . But since -2 ≤ x ≤ 2, this reduces to $2(x^2-4)$ .

a. Square cross sections will contribute a volume of

$\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x$

where ∆x is the thickness of the section. Then the volume would be

$\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}$

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

$\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x$

We end up with the same integral as before except for the leading constant:

$\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx$

Using the result of part (a), the volume is

$\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}$

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

$\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x$

and using the result of part (a) again, the volume is

$\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}$

7 0

2 years ago

Subtract. (−9.6x+7)−(7.3x−9) Enter your answer, in simplified form, in the box.Can somebody help me with this equation?

ZanzabumX [31]

-16.9x + 16 is the correct answer. You have to remove the parentheses, collect the like terms, and then simplify.

8 0

3 years ago

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∠3 and ∠4 are complementary adjacent angles. m∠4=49° What is the measure of ∠3 ?

neonofarm [45]

41°. 90-49=41 mmkmmmm

6 0

4 years ago

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