Question

Four point charges each having charge Q are located at the corners of a square having sides of length a.

Answer 1

Answer:

Explanation:

Given

Four Point charges are Placed at the corner of a square with side length a

Length of diagonal $a\sqrt{2}$

Distance of charge from center $\frac{a\sqrt{2}}{2}=\frac{a}{\sqrt{2}}$

Potential at the center due to four charges is given by

$V=\frac{4\cdot k\cdot Q}{\frac{a}{\sqrt{2}}}$

as all the four charges are equal and placed symmetrical about center

Work done required to bring a fifth charge q from infinity to the center of the square

$W=qV$

$W=\frac{4\sqrt{2}kQq}{a}$