A car of mass 998 kilograms moving in the positive y–axis at a speed of

Physics

2 answers:

aksik [14]3 years ago

8 0

The total momentum should come out to be <span>2.0 x 10^4 kilogram meters/second </span>

Hoochie [10]3 years ago

7 0

Answer:

Momentum in X direction = 20400 kg m/s

Explanation:

As we know that there is no external force on this system of two cars

so here the momentum of two cars will remains conserved always

So here we can say that initial total momentum of two cars in Y direction is given as

$P_y = mv_y$

$P_y = 998 (20) = 19960 kg m/s$

Now for X direction total momentum is given as

$P_x = mv_x$

$P_x = 1200(17) = 20400 kg m/s$

so here its momentum in x direction will always remains the same and its final momentum in x direction is given as

$P_x = 20400 kg m/s$

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A disk of mass m and moment of inertia of I is spinning freely at 6.00 rad/s when a second identical disk, initially not spinnin

Nadusha1986 [10]

Answer:

The angular speed of the new system is $3\,\frac{rad}{s}$ .

Explanation:

Due to the absence of external forces between both disks, the Principle of Angular Momentum Conservation is observed. Since axes of rotation of each disk coincide with each other, the principle can be simplified into its scalar form. The magnitude of the Angular Momentum is equal to the product of the moment of inertial and angular speed. When both disks begin to rotate, moment of inertia is doubled and angular speed halved. That is:

$I\cdot \omega_{o} = 2\cdot I \cdot \omega_{f}$