Lets use Dimensional analysis.

<h3>LHS:-</h3>
![\\ \sf\longmapsto s=\left[M^0LT^0\right]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20s%3D%5Cleft%5BM%5E0LT%5E0%5Cright%5D)
<h3>RHS</h3>

![\\ \sf\longmapsto \left[M^0LT^{-1}\right]\left[M^0L^0T^1\right]+\dfrac{1}{2}\left[M^0LT^{-2}\right]\left[M^0L^0T^1\right]^2](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cleft%5BM%5E0LT%5E%7B-1%7D%5Cright%5D%5Cleft%5BM%5E0L%5E0T%5E1%5Cright%5D%2B%5Cdfrac%7B1%7D%7B2%7D%5Cleft%5BM%5E0LT%5E%7B-2%7D%5Cright%5D%5Cleft%5BM%5E0L%5E0T%5E1%5Cright%5D%5E2)
![\\ \sf\longmapsto L+\dfrac{1}{2}\left[LT^{-2}\right]\left[T^2\right]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20L%2B%5Cdfrac%7B1%7D%7B2%7D%5Cleft%5BLT%5E%7B-2%7D%5Cright%5D%5Cleft%5BT%5E2%5Cright%5D)


![\\ \sf\longmapsto [L^1]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5BL%5E1%5D)
![\\ \sf\longmapsto \left[M^0LT^0\right]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cleft%5BM%5E0LT%5E0%5Cright%5D)
LHS=RHS
Hence verified
Answer:
Base units are defined units based on specific objects or events in the physical world. Derived units are defined by combining base units.
Base units are defined by a particular process of measuring a base quantity whereas derived units are defined as algebraic combinations of base units. For example, length is a base quantity in both SI and the English system, but the meter is a base unit in the SI system only.
we know that momentum is given as
P = mv
where P = momentum , m = mass , v = velocity
taking derivative both side relative to "t"
dP/dt = v (dm/dt)
we know that : dP/dt = F = force
hence
F = v (dm/dt)
given that :
dm/dt = rate of mass expelled = 1500 kg/s
v = velocity = 4 x 10⁴ m/s
hence , inserting the values in the above formula
F = (4 x 10⁴) (1500)
F = 6 x 10⁷ N
Since the lamps are identical, the current divides equally through them... 0.6A through each lamp.
Yes what do you need help on