<span> gravitational force varies based on 1/r^2
when you're double the distance =10,000 to 20,000, the force is 4 times smaller so on and so forth.
</span><span>As force is proportional to 1 / {distance squared}, the force will be 1 / 2^2 (i.e. 1/4) of the force at the reference distance (i.e. 1/4 * 600 = 150 lb)
</span>hope this helps
Answer:
4N
Explanation:
because the net force is greater in the right direction
The car's final speed in m/s after the acceleration is 30.
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<u>Given the following data:</u>
- Initial velocity, U = 0 m/s (since the cars starts from rest)
- Acceleration, a = 3 meter per seconds square.
To find the car's final speed in m/s after the acceleration, we would use the first equation of motion;
Mathematically, the first equation of motion is given by the formula;

<em>Final speed, V </em><em>=</em><em> 30 m/s</em>
Therefore, the car's final speed in m/s after the acceleration is 30.
Read more: brainly.com/question/8898885
Answer:
t = 3/8 seconds
Explanation:
h=-16t^2 - 10t+6
h= 0 when it hits the ground
0=-16t^2 - 10t+6
factor out a -2
0= -2(8t^2 +5t -3)
divide by -2
0 = (8t^2 +5t -3)
factor
0=(8t-3) (t+1)
using the zero product property
8t-3 = 0 t+1 =0
8t = 3 t= -1
t = 3/8 t= -1
t cannot be negative ( no negative time)
t = 3/8 seconds
We determine the electric potential energy of the proton by multiplying the net electric potential to the charge of the proton. The net electric potential is the difference of the final state to the that of the initial state. So, it would be 275 - 125 = 150 V.
electric potential energy = 150 (<span>1.602 × 10-19) = 2.4x10^-17 J</span>