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ss7ja [257]
3 years ago
13

A car of mass 998 kilograms moving in the positive y–axis at a speed of

Physics
2 answers:
aksik [14]3 years ago
8 0
The total momentum should come out to be  <span>2.0 x 10^4 kilogram meters/second </span>
Hoochie [10]3 years ago
7 0

Answer:

Momentum in X direction = 20400 kg m/s

Explanation:

As we know that there is no external force on this system of two cars

so here the momentum of two cars will remains conserved always

So here we can say that initial total momentum of two cars in Y direction is given as

P_y = mv_y

P_y = 998 (20) = 19960 kg m/s

Now for X direction total momentum is given as

P_x = mv_x

P_x = 1200(17) = 20400 kg m/s

so here its momentum in x direction will always remains the same and its final momentum in x direction is given as

P_x = 20400 kg m/s

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A wave sound is a longitudinal <span>wave.
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Why is Venus sometimes called Earth’s twin?
monitta

Answer:

B.

Venus is the same size and density.

Explanation:

It is becuase venus has the same size and density as earth

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The James Webb Space Telescope is positioned around 1.5 million kilometres from the Earth on the side facing away from the Sun.
Bad White [126]

The angular velocity depends on the length of the orbit and the orbital

speed of the telescope.

Response:

First question:

  • The angular velocity of the telescope is approximately <u>0.199 rad/s</u>

Second question:

  • The telescope should accelerates away by approximately F = <u>0.0005·m </u>

Third question:

  • <u>The pulling force between the Earth and the satellite</u>

<h3>What equations can be used to calculate the velocity and forces acting on the telescope?</h3>

The distance of the James Webb telescope from the Sun = 1.5 million kilometers from Earth on the side facing away from the Sun

The orbital velocity of the telescope = The Earth's orbital velocity

First question:

Angular \ velocity = \mathbf{\dfrac{Angle \ turned}{Time \ taken}}

The orbital velocity of the Earth = 29.8 km/s

The distance between the Earth and the Sun = 148.27 million km

The radius of the orbit of the telescope = 148.27 + 1.5 = 149.77

Radius of the orbit, r = 149.77 million kilometer from the Sun

The length of the orbit of the James Webb telescope = 2 × π × r

Which gives;

r = 2 × π × 149.77 million kilometers ≈ 941.03 million kilometers

Therefore;

Angular \ velocity = \dfrac{29.8}{941.03}\times 2 \times \pi \approx 0.199

  • The angular velocity of the telescope, ω ≈ <u>0.199 rad/s</u>

Second question:

Centrifugal force force, F_{\omega} = m·ω²·r

Which gives;

F_{\omega} = m \cdot \dfrac{28,500^2 \, m^2/s^2}{149.77 \times 10^9 \, m} \approx 0.0054233 \cdot m

Gravitational \ force,  F_G = \mathbf{G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}}

Universal gravitational constant, G = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²

Mass of the Sun = 1.989 × 10³⁰ kg

Which gives;

F_G = 6.67408 \times 10^{-11} \times \dfrac{1.989 \times 10^{30} \times m}{149.77 \times 10^9} \approx   0.00592 \cdot m

Which gives;

F_{\omega} < F_G, therefore, the James Webb telescope has to accelerate away from the Sun

F = \mathbf{F_{\omega}} - \mathbf{F_G}

The amount by which the telescope accelerates away is approximately 0.00592·m - 0.0054233·m ≈ <u>0.0005·m (away from the Sun)</u>

Third part:

Other forces include;

  • <u>The force of attraction between the Earth and the telescope </u>which can contribute to the the telescope having a stable orbit at the given speed.

Learn more about orbital motion here:

brainly.com/question/11069817

3 0
3 years ago
I need help with the last question- it’s very simple
77julia77 [94]

You calculated the density correctly.

When you drop anything into a fluid . . .

-- If the object is MORE dense than the fluid, it sinks.

-- If the object is LESS dense than the fluid, it floats.

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4 years ago
Why is it important for scientist to do research?
sweet-ann [11.9K]

Answer:

Because if they dont research first they will be unprepared

Explanation:

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