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ss7ja [257]
3 years ago
13

A car of mass 998 kilograms moving in the positive y–axis at a speed of

Physics
2 answers:
aksik [14]3 years ago
8 0
The total momentum should come out to be  <span>2.0 x 10^4 kilogram meters/second </span>
Hoochie [10]3 years ago
7 0

Answer:

Momentum in X direction = 20400 kg m/s

Explanation:

As we know that there is no external force on this system of two cars

so here the momentum of two cars will remains conserved always

So here we can say that initial total momentum of two cars in Y direction is given as

P_y = mv_y

P_y = 998 (20) = 19960 kg m/s

Now for X direction total momentum is given as

P_x = mv_x

P_x = 1200(17) = 20400 kg m/s

so here its momentum in x direction will always remains the same and its final momentum in x direction is given as

P_x = 20400 kg m/s

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A car’s tire rotates 5.25 times in 3 seconds. What is the tangential velocity of the tire?
Lena [83]

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire which is 11(r) m/s.

<h3>Angular velocity of the tire</h3>

The angular velocity of the tire is the rate of change of angular displacement of the tire with time.

The magnitude of the angular velocity of the tire is calculated as follows;

ω = 2πN

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ω =  11 rad/s

<h3>Tangential velocity of the tire</h3>

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire.

The magnitude of the tangential velocity is caculated as follows;

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v = 11r m/s

Learn more about tangential velocity here: brainly.com/question/25780931

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3 years ago
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Explanation:

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