Answer:
1.2826 x 10^-13 m
Explanation:
Here, k be the kinetic energy and m be the mass
K = 50 KeV = 50 x 1.6 x 10^-16 J = 80 x 10^-16 J
m = 1.67 x 10^-27 kg
λ = 1.2826 x 10^-13 m
A car of mass 998 kilograms moving in the positive y–axis at a speed of
2 answers:
Answer:
Momentum in X direction = 20400 kg m/s
Explanation:
As we know that there is no external force on this system of two cars
so here the momentum of two cars will remains conserved always
So here we can say that initial total momentum of two cars in Y direction is given as
Now for X direction total momentum is given as
so here its momentum in x direction will always remains the same and its final momentum in x direction is given as
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Answer:
- k = 167.33 N/m
Explanation:
- The radio waves have a fixed relationship between the propagation speed (the speed of light in vacuum), the frequency and the wavelength, as follows:
- v = c = λ*f
where c= speed of light in vacuum = 3*10⁸ m/s, λ = wavelength =
4.92*10⁷ m.
Solving for f, we get the frequency of the radio waves:
f = 6.1 Hz
- Now, from the Hooke's law, we know that the mass attached at the end of the spring oscillates with an angular frequency defined by a fixed relationship between the spring constant k and the mass m, as follows:
- Now, we know that there exists a fixed relationship between the angular frequency and the frequency, as follows:
- We also know that f in (2) is the same that we got for the radio waves, so replacing (2) in (1), and rearranging terms, we can solve for k, as follows: