2 questions, brainliest for both correct! please: only answer if you are sure of the answer!! :)
2 answers:
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Answer:
The farther star will appear 4 times fainter than the star that is near to the observer.
Explanation:
Since it is given that the luminosity of the 2 stars is same thus they radiate the same energy per unit time
Consider a spherical wave front of energy 'E' that leaves both the stars (Both radiate 'E' as they have same luminosity)
This Energy is spread over the whole surface area of sphere Thus when the wave front is at a distance 'r' the energy per unit surface area is given by
For the star that is twice away from the earth the distance is '2r' thus we will receive an energy given by
Hence we sense it as 4 times fainter than the nearer star.
Answer:
- Current = 0.33 A
Explanation:
- For diagram refer the attachment.
It is given that five cells of 2V are connected in series, so total voltage of the battery:
Three resistor of 5, 10
, 15
are connected in Series, so the net resistance:
According to ohm's law:
On substituting resultant voltage (V) as 10 V and resultant resistant, as 30 we get:
The electric current passing through the above circuit when the key is closed will be <u>0.33 A</u>
