Since there are equal numbers of pieces, the chances of Julio getting a red on the first pull is 12/24 or 1/2 (reduced)
However on the second pull there are only 11 reds (Julio pulled one out) out of 23 remaining pieces so the chances of pulling the second red are 11/23
Now multiply those possibilities:
1/2 x 11/23 and you will get 11/46 which is the probability of pulling two reds in a row. 11/46 is the answer.
Answer:
72 alligators, 128 turtles
Step-by-step explanation:
When you put the words into the form of an equation, with a being alligators, you get
3a-16=200
So you have to do 'letters left numbers right'. This gives you
3a=216
Now you have to divide. 216 divided by 3 equals 72. So there are 72 alligators. 200 minus 72 equals 128, so there are 128 turtles
Answer:
30
Step-by-step explanation:
Hey There!
To find the area of a triangle we divide the product of the height and base by 2
6x10=60
60/2=30
the area of the triangle is 30 :)
Answer:
.
Don required 673 of 9 inch tiles to cover an area of 400 square feet, when spacing the tiles a quarter inch apart.
Step-by-step explanation:
Given:
The given function is:
![t(A)=\frac{144}{9.25^2}A](https://tex.z-dn.net/?f=t%28A%29%3D%5Cfrac%7B144%7D%7B9.25%5E2%7DA)
Here,
represent the area to be covered,
represent the number of tiles required to cover the given area.
So, if
, it means that the area to be covered is 400 square units.
Now, if we find
, it means we need to find the number of 9 inch tiles to cover area of 400 units.
So, we plug in 400 for
to evaluate
.
![t(400)=\frac{144}{9.25^2}\times 400=\frac{144\times 400}{85.5625}=\frac{57600}{85.5625}=673.19\approx673](https://tex.z-dn.net/?f=t%28400%29%3D%5Cfrac%7B144%7D%7B9.25%5E2%7D%5Ctimes%20400%3D%5Cfrac%7B144%5Ctimes%20400%7D%7B85.5625%7D%3D%5Cfrac%7B57600%7D%7B85.5625%7D%3D673.19%5Capprox673)
Therefore, it means that 673 of 9 inch tiles are required to cover an area of 400 square feet, when spacing the tiles a quarter inch apart.
Please consider the complete question.
A parking lot in the shape of a trapezoid has an area of 12,052.1 square meters. The length of one base is 82.4 meters and the length of the base is 108.6 meters. What is the width of the parking lot
We will use area of trapezoid to formula to solve our given problem.
, where
a and b represents parallel sides of trapezoid,
h = height of trapezoid.
Width of the trapezoid will be equal to height.
Upon substituting our given values in above formula, we will get:
![12,052.1=\frac{1}{2}(82.4+108.6)\times h](https://tex.z-dn.net/?f=12%2C052.1%3D%5Cfrac%7B1%7D%7B2%7D%2882.4%2B108.6%29%5Ctimes%20h)
![12,052.1\cdot 2=2\cdot \frac{1}{2}(82.4+108.6)\times h](https://tex.z-dn.net/?f=12%2C052.1%5Ccdot%202%3D2%5Ccdot%20%5Cfrac%7B1%7D%7B2%7D%2882.4%2B108.6%29%5Ctimes%20h)
![24104.2=(191)\times h](https://tex.z-dn.net/?f=24104.2%3D%28191%29%5Ctimes%20h)
![\frac{24104.2}{191}=\frac{(191)\times h}{191}](https://tex.z-dn.net/?f=%5Cfrac%7B24104.2%7D%7B191%7D%3D%5Cfrac%7B%28191%29%5Ctimes%20h%7D%7B191%7D)
![126.2=h](https://tex.z-dn.net/?f=126.2%3Dh)
Therefore, the width of the parking lot is 126.2 meters.